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olga_2 [115]
2 years ago
9

Processes that increase the density of seawater include evaporation and _____.

Chemistry
2 answers:
BabaBlast [244]2 years ago
8 0
Processes that increase the density of seawater include evaporation and C) formation of sea ice. 
Elena L [17]2 years ago
3 0
Correct Answer: option C: Formation of sea ice

Reason: 
<span> In cold regions, changes in salinity alters the water present in ocean. Further, water density also changes with temperature. In general, water density in ocean water increases with decreasing temperature. This is because,  when salt is ejected into the ocean as sea ice forms, the water's salinity increases. Since, salt water is heavier, the density of the water increases.</span>
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Emily wanted to see what battery lasted the longest. She put each battery into a clock and recorded the time that the clock stop
Andru [333]

Answer:

independent variable -- different batteries

dependent variable -- the time that clock stop

Explanation:

In an experiment or a research study, there are two type of variables that can affect the result of the experiment or the conclusion. They are independent variable and the dependent variable.

An independent variable may be defined as that variable in an experiment which can be changed or can be controlled in the scientific experiment in order to test the effect on the dependent variable. It cannot be changed by other variables.

On the other hand, dependent variable are those are those which can be altered or change that can affect the experiment.

In the context, Emily uses  the different types of the batteries as an independent variable and the time where the clock stopped in the dependent variable in her research.

6 0
3 years ago
The hydrogen-line emission spectrum includes a line at a wavelength of 434 nm. What is the energy of this radiation? (h= 6.626 x
Andrews [41]
Wavelength = 434nm = 434 x 10⁻⁹m
planck's constant = <span>h= 6.626 x 10 ⁻³⁴ J
E =?
by using the formula;
E = hc /</span>λ
value for c is 3 x 10⁸ m/s
E = (6.626 x 10 ⁻³⁴ J)(3 x 10⁸ m/s) / 434 x 10⁻⁹m
E = 1.9878 x 10⁻²⁵ / 434 x 10⁻⁹m
E = 4.58 x 10⁻¹⁹ joules

6 0
3 years ago
Easy questions ha chemistry
joja [24]

Answer:

B

A

D

Explanation:

3 0
3 years ago
Read 2 more answers
A graduated cylinder was filled with 25.0 mL of water. A solid object was immersed in the cylinder, raising the water level to 3
yawa3891 [41]

Answer:

Density of the object is 8759.494 grams/L

Explanation:

As we know density of an object is mass of the object divided by its volume

Given

Volume of the object is equal to the change in volume of water with in the cylinder when the object was immersed in water.

Hence, volume of object is equal to

32.9 -25 = 7.9 mL

Mass of the object is 69.2 grams

Density

= \frac{69.2}{7.9 *10^{-3}}\\= 8759.494 grams/L

Density of the object is 8759.494 grams/L

7 0
3 years ago
What is the volume of 14.0g of nitrogen gas at STP?
lozanna [386]

Answer:

  • <em>The volume of 14.0 g of nitrogen gas at STP is </em><u><em>11.2 liter.</em></u>

Explanation:

STP stands for standard pressure and temperature.

The International Institute of of Pure and Applied Chemistry, IUPAC changed the definition of standard temperature and pressure (STP) in 1982:

  •   Before the change, STP was defined as a temperature of 273.15 K and an absolute pressure of exactly 1 atm (101.325 kPa).

  •    After the change, STP is defined as a temperature of 273.15 K and an absolute pressure of exactly 105 Pa (100 kPa, 1 bar).

Using the ideal gas equation of state, PV = nRT you can calculate the volume of one mole (n = 1)  of gas. With the former definition, the volume of a mol of gas at STP, rounded to 3 significant figures, was 22.4 liter. This is classical well known result.

With the later definition, the volume of a mol of gas at STP is 22.7 liter.

I will use the traditional measure of 22.4 liter per mole of gas.

<u>1) Convert 14.0 g of nitrogen gas to number of moles:</u>

  • n = mass in grams / molar mass
  • Atomic mass of nitrogen: 14.0 g/mol
  • Nitrogen gas is a diatomic molecule, so the molar mass of nitrogen gas = molar mass of N₂ = 14.0 × 2 g/mol = 28.0 g/mol
  • n = 14.0 g / 28.0 g/mol = 0.500 mol

<u>2) Set a proportion to calculate the volume of nitrogen gas:</u>

  • 22.4 liter / mol = x  / 0.500 mol
  • Solve for x: x = 0.500 mol × 22.4 liter / mol = 11.2 liter.

<u>Conclusion:</u> the volume of 14.0 g of nitrogen gas at STP is 11.2 liter.

6 0
3 years ago
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