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olga_2 [115]
3 years ago
9

Processes that increase the density of seawater include evaporation and _____.

Chemistry
2 answers:
BabaBlast [244]3 years ago
8 0
Processes that increase the density of seawater include evaporation and C) formation of sea ice. 
Elena L [17]3 years ago
3 0
Correct Answer: option C: Formation of sea ice

Reason: 
<span> In cold regions, changes in salinity alters the water present in ocean. Further, water density also changes with temperature. In general, water density in ocean water increases with decreasing temperature. This is because,  when salt is ejected into the ocean as sea ice forms, the water's salinity increases. Since, salt water is heavier, the density of the water increases.</span>
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How many molecules of excess reactant remain after the reaction is complete?
vazorg [7]
8


It’s 8 bc I said it was 8 ;)
5 0
3 years ago
A neutralization reaction is a reaction between choose. That results in the formation of choose. And choose.
andrey2020 [161]

Neutralization reaction is the reaction that occur between acid and base.

<h3>What is Neutralization reaction?</h3>

Neutralization reaction is the reaction that take place between acid and base to produce salt and water. For examples HCl react with NaOH to produce NaCl and H2O

Therefore, Neutralization reaction is the reaction between acid and base.

The question is not complete but the option are gotten from another website.

Here are the options.

  • an acid and a base
  • a fuel and oxygen
  • an acid and a metal
  • a salt and a base

Learn more about neutralization from the link below.

brainly.com/question/4090568

8 0
2 years ago
A gas sample of 2.31 atm of oxygen gas and 3.75 atm of hydrogen gas that react to form water vapor. Assume the volume of the con
maxonik [38]

Mole fraction of Oxygen=0.381

Mole fraction of Oxygen= (range of moles of oxygen) ÷(general moles)

also, mole fraction of oxygen = (partial stress of oxygen) ÷ (total strain)

consequently , mole fraction of Oxygen= (2.31 atm)÷(2.31 atm + 3.75 atm)

= 0.381

The mole fraction may be calculated by means of dividing the variety of moles of 1 element of a solution by the entire quantity of moles of all the additives of a solution. It is cited that the sum of the mole fraction of all of the components inside the solution should be identical to 1.

Mole fraction is a unit of awareness. in the solution, the relative amount of solute and solvents are measured by way of the mole fraction and it's far represented through “X.” The mole fraction is the variety of moles of a selected aspect inside the answer divided by way of the entire range of moles in the given answer.

Mole fraction is the ratio between the moles of a constituent and the sum of moles of all ingredients in a mixture. Mass fraction is the ratio between the mass of a constituent and the full mass of a mixture.

The question is incomplete. Please read below to find the missing content.

Assuming that only the listed gases are present, what would the mole fraction of oxygen gas be for each of the following situations? A gas sample of 2.31 atm of oxygen gas and 3.75 atm of hydrogen gas react to form water vapor. Assume the volume of the container and the temperature inside the container does not change.

Learn more about the mole fraction here brainly.com/question/14783710

#SPJ1

4 0
2 years ago
Balancing chemical equations
mojhsa [17]

<span>2H2 + O2 → 2H2O</span>

<span>
</span>

<span>okay???</span>

<span>
</span>

4 0
3 years ago
if a sample of gas at 25.2 c has a volume of 536mL at 637 torr, what will its volume be if the pressure is increased to 712 torr
nignag [31]
Considering ideal gas:
PV= RTn

T= 25.2°C = 298.2 K

P1= 637 torr = 0.8382 atm

V1= 536 mL = 0.536 L

:. R=0.082 atm.L/K.mol

:. n= (P1V1)/(RT) = ((0.8382 atm) x (0.536 L))/
((0.082 atmL/Kmol) x (298.2K))

:. n= O.0184 mol

Then,
P2= 712 torr = 0.936842 atm

V2 = RTn/P2 = [(0.082atmL/
Kmol) x (298.2K) x (0.0184mol) ]/(0.936842atm)

:.V2 = 0.4796 L
OR
V2 = 479.6 ml

6 0
3 years ago
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