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olga_2 [115]
3 years ago
9

Processes that increase the density of seawater include evaporation and _____.

Chemistry
2 answers:
BabaBlast [244]3 years ago
8 0
Processes that increase the density of seawater include evaporation and C) formation of sea ice. 
Elena L [17]3 years ago
3 0
Correct Answer: option C: Formation of sea ice

Reason: 
<span> In cold regions, changes in salinity alters the water present in ocean. Further, water density also changes with temperature. In general, water density in ocean water increases with decreasing temperature. This is because,  when salt is ejected into the ocean as sea ice forms, the water's salinity increases. Since, salt water is heavier, the density of the water increases.</span>
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Which choice contains a FALSE statment? A. For the vaporization of liquid benzene ΔH is positive. B. For the formation of 1 mol
ser-zykov [4K]

Answer:

B is False

Explanation:

In physical chemistry we always look from system's perspective, so if we heat something ΔH is positive and if the system gives heat out then ΔH is negative.

A. We have to give energy to benzene to evaporate it. Statement true.

B. If heat is absorbed then the enthalpy must be positive.

C. The heat is absorbed then ΔH is positive.

D. Usually for burning heat is exposed from system. So enthalpy is negative.

E. Obvious

7 0
3 years ago
_Na2B407 + _H2SO4(aq) +
myrzilka [38]

Answer:

Na2B4O7 + H2SO4 + 5H2O → 4H3BO3 + Na2SO4  

Explanation:

The unbalanced equation is given as;

Na2B4O7 + H2SO4(aq) + H2O → H3BO3(s) + Na2SO4(aq)

Balancing the equation of the reaction involves making sure the number of moles of elements in the reactants to be equal to the number of moles of the element of the products.

The balanced equation is given as;

Na2B4O7 + H2SO4 + 5H2O → 4H3BO3 + Na2SO4  

3 0
3 years ago
A rectangular block of copper metals weigh 673.37g. The dimensions of the block are 8.4cm by 5.5cm by 4.6cm. From this data, wha
Sever21 [200]
Density is g/cm^3 so you get the volume of the block:
4.6×5.5×8.4= 212.52cm^3


Then you take grams÷cm^3:
\frac{673.37g}{212.52 {cm}^{3} }  =  \frac{3.168501g}{1 {cm}^{3} }  =  \frac{3.17g}{ {cm}^{3} }



8 0
3 years ago
What color element symbol designates elements that are a gas at a given temperature?
kotegsom [21]
Green and purple because they are non-metals or gases
5 0
3 years ago
Sodium sulfate dissolves as follows: Na2SO4(s) → 2Na (aq) SO42- (aq). How many moles of Na2SO4 are required to make 1.0 L of sol
never [62]

Answer:

0.05 moles of sodium sulfate are required.

Explanation:

Na_2SO_4(s) \rightarrow 2Na^+ (aq) SO_4^{2-} (aq)

Concentration of sodium ions in 1 L = 0.10 M

0.10 M=\frac{\text{Moles of sodium ions}}{1.0 L}

Moles of sodium ions = 0.10 mol

1 mole of sodium  sulfate gives 2 moles of sodium ions.

Then 0.10 mol of sodium ions will be given by:

\frac{1}{2}\times 0.10 mol=0.05 mol

0.05 moles of sodium sulfate are required.

4 0
3 years ago
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