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sertanlavr [38]
3 years ago
11

In an attempt to maximize the yield of methanol (amount of methanol produced), a chemist would try to shift the equilibrium as f

ar to the right as possible. Which of the following would accomplish this? a. heating the mixture b. adding an excess of carbon monoxide c. removing the methanol as it is formed d. adding a substance that reacts with carbon monoxide
Chemistry
1 answer:
MakcuM [25]3 years ago
3 0

Answer:

removing the methanol as it is formed

Explanation:

One of the ways to drive the equilibrium position towards the right is to remove one of the products formed.

According to Me Chatelier's principle, the imposition of a constraint on a system in a equilibrium causes the equilibrium position to shift towards a new position that annuls the constraint. Hence, removing the methanol causes the equilibrium position to shift to the far right in order to reestablish equilibrium according to Le Chatelier's principle.

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Answer:

c

Explanation:

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Match the following names of glassware with what you would use them for.
Valentin [98]

Answer:

A) Graduated pipette – Glassware used to accurately transfer small volumes.

B) Volumetric pipette – Glassware used to accurately transfer a small, single volume.

C) Beaker – Glassware best used when greater access to the contents is needed.

D) Buret – Glassware used to deliver a volume not known in advance.

E) Erlenmeyer flask – Glassware used to prevent splashing or evaporation.

F) Volumetric flask – Glassware used to make accurate solutions.

Explanation:

Graduated pipette – Glassware used to accurately transfer small volumes.

A graduated pipette is a pipette, which has a scale that shows its volume marked along the tube. It is used to transfer small volumes accurately.

Volumetric pipette – Glassware used to accurately transfer a small, single volume.

A volumetric pipette is a pipette, which has a ring like marking that is its calibrated volume. So it is used to transfer a single and small volume only. This pipette is used in volumetric analysis.

Beaker – Glassware best used when greater access to the contents is needed.

Beaker is the most widely used glassware in the laboratory. They are used to transfer large volume with less accuracy. They are of different sizes depends on the size of volumes ranging from 10 mL to 1000 mL.

Buret – Glassware used to deliver a volume not known in advance.

Buret is the most important glassware in the quantitative analysis. It has a glass tube with scale which measures the volume and a stopcock at one end from which the solvent is dispersed. It is used to measure the volume of the liquid during the titration in the quantitative analysis.

Erlenmeyer flask – Glassware used to prevent splashing or evaporation.

The most common names of Erlenmeyer flask are conical flask and titration flask. This flask has flat bottom, conical body and cylindrical neck which prevent splashing and evaporation. This flask is used in the titration process in the quantitative analysis. The solvent from the buret is delivered into the conical flask during the titration process.

Volumetric flask – Glassware used to make accurate solutions.

The volumetric flask is also an important glassware in the analytical laboratory. It is used to prepare standard solutions. It is a flask which has a ring like marking that is its calibrated volume. The mentioned volume of volumetric flask is calibrated to have accurate volume.

3 0
3 years ago
a radio controlled airplane is moving at a velocity of 23 m/s. it accelerates to a velocity of 85 m/s in 9.3 seconds. what accel
tatuchka [14]

I will show you a method to find a velocity of anything:-


Find average velocity when acceleration is constant.

Set up an equation with position and time instead.

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Calculate the change in time.

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7 0
3 years ago
A 22.0 mLmL sample of a 1.16 MM potassium sulfate solution is mixed with 14.8 mLmL of a 0.860 MM barium nitrate solution and thi
dezoksy [38]

Answer:

The limiting reactant is Ba(NO3)2

The theoretical yield BaSO4 is 2.97 grams

The percent yield of the reaction is 86.5 %

Explanation:

Step 1: Data given

Volume of a 1.16 M potassium sulfate solution (K2SO4) = 22.0 mL = 0.022 L

Volume of a 0.860 M barium nitrate solution (Ba(NO3)2 = 14.8 mL = 0.0148 L

The solid BaSO4 is collected, dried, and found to have a mass of 2.57 grams

Step 2: The balanced equation

K2SO4(aq) + Ba(NO3)2(aq) → BaSO4(s) + 2KNO3(aq)

Step 3: Calculate moles

Moles = volume * molarity

Moles K2SO4 = 0.022 L * 1.16 M

Moles K2SO4 = 0.02552 moles

Moles Ba(NO3)2 = 0.0148 L * 0.860 M

Moles Ba(NO3)2 = 0.012728 moles

Step 4: Calculate the limiting reactant

For 1 mol K2SO4 we need 1 mol Ba(NO3)2 to produce 1 mol BaSO4 and 2 moles KNO3

Ba(NO3)2 is the limiting reactant. It will completely be consumed. (0.012728 moles) . K2SO4 is in excess. There will remain 0.02552 - 0.012728 = 0.012792 moles

Step 5: Calculate moles BaSO4

‬For 1 mol K2SO4 we need 1 mol Ba(NO3)2 to produce 1 mol BaSO4 and 2 moles KNO3

For 0.012728 moles Ba(NO3)2 we'll have 0.012728 moles BaSO4

Step 6: Calculate mass BaSO4

Mass BasO4 = moles BaSO4 * molar mass BaSO4

Mass BaSO4 =  0.012728 moles *  233.38 g/mol

Mass BaSO4 = 2.97 grams

Step 7: Calculate the percent yield

% yield = (actual yield / theoretical yield ) * 100 %

% yield = ( 2.57 grams / 2.97 grams ) * 100 %

% yield = 86.5 %

The limiting reactant is Ba(NO3)2

The theoretical yield BaSO4 is 2.97 grams

The percent yield of the reaction is 86.5 %

7 0
3 years ago
Ethylenediamine is a bidentate ligand. The oxalate group, used in this experiment was also a didentate ligand. The structure of
Murljashka [212]

Answer:

Ethylene diamine will bond to the Central metal via a lone pairs of electrons on nitrogen

Explanation:

Complexes are formed by coordinate bond formation. Before a coordinate bond is formed, one of the species must have a lone lair of electrons available for donation into empty orbitals on the central metal.

Ethylene diammine contains nitrogen which has a lone pair of electrons. The two lone pairs on the two nitrogen atoms can bond with the central metal. This makes ethylene diammine a bidentate ligand (two bonding atoms).

5 0
3 years ago
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