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sertanlavr [38]
3 years ago
11

In an attempt to maximize the yield of methanol (amount of methanol produced), a chemist would try to shift the equilibrium as f

ar to the right as possible. Which of the following would accomplish this? a. heating the mixture b. adding an excess of carbon monoxide c. removing the methanol as it is formed d. adding a substance that reacts with carbon monoxide
Chemistry
1 answer:
MakcuM [25]3 years ago
3 0

Answer:

removing the methanol as it is formed

Explanation:

One of the ways to drive the equilibrium position towards the right is to remove one of the products formed.

According to Me Chatelier's principle, the imposition of a constraint on a system in a equilibrium causes the equilibrium position to shift towards a new position that annuls the constraint. Hence, removing the methanol causes the equilibrium position to shift to the far right in order to reestablish equilibrium according to Le Chatelier's principle.

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I have these orgo problems for homework and I have no idea where to even begin. We have to find missing reagents and products ba
almond37 [142]

Answer:

Honestly makes no sense sorry :(

Explanation:

I can try though.. There are three types of selectivity possible for any synthesis: (i) Chemoselectivity is deciding which group reacts. (ii) Regioselectivity is where the reaction takes place in that group. (iii) Stereoselectivity is how the group reacts with respect to the stereochemistry of the product.

A stereospecific mechanism specifies the stereochemical outcome of a given reactant, whereas a stereoselective reaction selects products from those made available by the same, non-specific mechanism acting on a given reactant. Of stereoisomeric reactants, each behaves in its own specific way.

I tried to explain it the best I could.

Hopefully this helps you :)

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5 0
3 years ago
What is responsible for the whistling sound that often accompanies firework?
Naya [18.7K]
The wistle is coming from all the chemicals including the fire you use to light the firework and a chemcial reaction is occuring which is the sound that is made because of this
8 0
3 years ago
Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT
marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

(c) L(T, α) = 60·α·T - 9000·α + 60

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

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Phosphorus that is stored in organisms
Mumz [18]

Explanation:

B. Recycles slowly

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3 years ago
If 25.5g of sodium thiosulphate was dissolved in 40g of distilled water at 25°C,
zhenek [66]

Answer:

Formula: Na2S2O3

we get solubility.

Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g .

Solution given:

mass of sodium thiosulphate [m1]=25.5g

mass of water [m2]=40g

at temperature [t]=25°C

we have

<u>solubility in g/dm^3</u> :\frac{solute in gram}{solvent in gram} *100

  • =\frac{25.5}{40}*100
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<u>solubility in g/dm^3 :63.75g/dm³</u>

<u>n</u><u>o</u><u>w</u>

solubility of the solute in mol/dm^3=:63.75g/dm³/178=0.4 mol/dm³

6 0
3 years ago
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