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sertanlavr [38]
4 years ago
11

In an attempt to maximize the yield of methanol (amount of methanol produced), a chemist would try to shift the equilibrium as f

ar to the right as possible. Which of the following would accomplish this? a. heating the mixture b. adding an excess of carbon monoxide c. removing the methanol as it is formed d. adding a substance that reacts with carbon monoxide
Chemistry
1 answer:
MakcuM [25]4 years ago
3 0

Answer:

removing the methanol as it is formed

Explanation:

One of the ways to drive the equilibrium position towards the right is to remove one of the products formed.

According to Me Chatelier's principle, the imposition of a constraint on a system in a equilibrium causes the equilibrium position to shift towards a new position that annuls the constraint. Hence, removing the methanol causes the equilibrium position to shift to the far right in order to reestablish equilibrium according to Le Chatelier's principle.

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Which of the following equations demonstrates the law of conservation of mass?
VLD [36.1K]

Answer:

Mg + O2 ---> MgO

Explanation:  V2O5 + CaS → CaO + V2S5. 5V2O5 + 5CaS → 10CaO + 5V2S5. 3V2O5 + 3CaS → 3CaO + 3V2S5.

7 0
3 years ago
The number of _______ in an atom of an element is the element's atomic number.
sergiy2304 [10]
The number of: Protons.
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3 years ago
Calculate the moles of HCl in 15 mL of a 0.50 M solution.
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Explanation:

\tiny\implies Molarity =  \dfrac{no. \: of \: moles \: of \: solute \times 1000}{volume \: of \: the \: solution \: (in \: ml)}

\tiny\implies 0.50 =  \dfrac{no. \: of \: moles \: of \: solute \times 1000}{15}

\tiny\implies no. \: of \: moles \: of \: solute \times 1000  =  0.50 \times 15

\tiny\implies no. \: of \: moles \: of \: solute \times 1000  =  7.5

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4 0
3 years ago
I would really appreciate it if someone helped me out with this question.
marusya05 [52]

Answer:

a) 0.085 moles of Fe₂(SO₄)₃  are produced.

b) Percent yield = 54.4%

Explanation:

Given data:

Moles of FePO₄ = 0.17mol

Number of moles of Fe₂(SO₄)₃ = ?

Solution:

Chemical equation:

2FePO₄ + 3Na₂SO₄           →       Fe₂(SO₄)₃ + 2Na₃PO₄

Now we will compare the moles of FePO₄ with Fe₂(SO₄)₃

                       FePO₄            :         Fe₂(SO₄)₃

                           2                 :                1

                         0.17               :           1/2×0.17 = 0.085 mol

From 0.17 moles of FePO₄ 0.085 moles of Fe₂(SO₄)₃  are produced.

b)

Given data:

Mass of  Fe₂(SO₄)₃  produced = 18.5 g

Percent yield = ?

Solution:

Theoretical yield of Fe₂(SO₄)₃:

Mass = number of moles × molar mass

Mass = 0.085 mol × 399.88 g/mol

Mass = 34 g

Percent yield:

Percent yield = (actual yield / theoretical yield )× 100

Percent yield = (18.5 g / 34 g) × 100

Percent yield = 54.4%

7 0
3 years ago
Which type of chemical reaction is represented by this equation
Xelga [282]

Answer:

2

Explanation:

2 balances out the equation

4 0
2 years ago
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