Answer:
See below.
Explanation:
They both have 1 valency electron so will be metallic and in the same Group (Group 1) of the Periodic Table, so will have similar properties.
Answer:
Large molecules tend to have greater boiling points because the London dispersion forces are stronger within.
Explanation:
Answer:
Number of moles of Fe = 10 mol
Number of moles of CO₂ = 15 mol
Explanation:
Given data:
Number of moles of iron oxide = 5 mol
Number of moles of carbon monoxide = 25 mol
Number of moles of product = ?
Solution:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Now we will compare the moles of reactant with product.
Fe₂O₃ : Fe
1 : 2
5 : 2×5 = 10 mol
Fe₂O₃ : CO₂
1 : 3
5 : 3×5 = 15 mol
CO : Fe
3 : 2
25 : 2/3×25 = 16.7 mol
CO : CO₂
3 : 3
25 : 25
Less number of moles of Fe and CO₂ are formed by iron oxide thus it will act as limiting reactant while CO is inn excess.
Answer:
Plants
Explanation:
Plants, part of the biosphere, grow in the soil, which is part of the geosphere
hope this helped :)
Answer:
90.3 kJ/mol
Explanation:
Let's consider the following thermochemical equation.
2 NO(g) + O₂(g) → 2 NO₂(g) ∆H°rxn = –114.2 kJ
We can find the standard enthalpy of formation for NO using the following expression.
∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × ΔH°f(O₂(g))
∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × 0 kJ/mol
∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g))
ΔH°f(NO(g)) = (2 mol × ΔH°f(NO₂(g)) - ∆H°rxn) / 2 mol
ΔH°f(NO(g)) = (2 mol × 33.2 kJ/mol + 114.2 kJ) / 2 mol
ΔH°f(NO(g)) = 90.3 kJ/mol