Question

Arrange the following substances in order of decreasing magnitude of lattice energy. Rank the compounds in order of decreasing magnitude of lattice energy.a. MgOb. CaOc. NaFd. KCl

Answer 1

The lattice energy of the compounds is distributed in the following decreasing order of magnitude: MgO > CaO > NaF > KCl.

KCl or NaF, which has a higher lattice energy?

The lattice energy increases with increasing charge and decreasing ion size.(Refer to Coulomb's Law.)MgF2 > MgO.Following that, we can examine NaF and KCl (both of which have 1+ and 1-charges), as well as atomic radii.NaF will have a larger LE than KCl since Na is smaller then K and F was smaller than Cl.

MgO or CaO, which has a larger lattice energy?

MGO is more difficult than CaO, hence.This is because "Mg" (two-plus) ions are smaller than "Ca" (two-plus) ions in size.MgO has higher lattice energy as a result.

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