What is the partial pressure of helium gas in a mixture that contains 8.00 grams of helium and 8.60 mol argon gas with a total p
1 answer:
Answer:
Explanation:
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In this case, we can identify the solution to this problem via the Dalton's rule because the partial pressure of helium is given by:
Whereas the mole fraction of helium is calculated by firstly obtaining the moles and then the mole fraction:
Then, we calculate the partial pressure as shown below:
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Charles law gives the relationship between temperature and volume of gases. It states that the volume of gas is directly proportional to temperature at constant pressure.
V / T = k
where V - volume and T - temperature in Kelvin and k - constant
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
T1 - 20 °C + 273 = 293 K
substituting these values in the equation
T = 586 K
temperature in celsius = 586 K - 273 = 313 °C
new temperature is 313 °C
V / T = k
where V - volume and T - temperature in Kelvin and k - constant
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
T1 - 20 °C + 273 = 293 K
substituting these values in the equation
T = 586 K
temperature in celsius = 586 K - 273 = 313 °C
new temperature is 313 °C