Answer:
yes. can always be separated
Answer:
The image is formed at 0.44 m in front of the mirror
magnification (M) = 0.44
Explanation:
Applying, mirror formular
1/f = (1/u)+(1/v).................... Equation 1
Where f = Focal length of the convex mirror, u = object distance, v = image distance.
Using the real is positive convection,
From the question,
Given: f = -1.6/2 = -0.8 m( The focal length of a convex mirror is vitual), u = 1.0 m
Substitute these values into equation 1
-1/0.8 = (1/v)+(1/1)
Solve for v
1/v = 1.25+1
1/v = 2.25
v = 1/2.25
v = 0.44 m
Hence the image is formed at 0.44 m in front of the mirror
Magnification (M) = v/u
m = 0.44/1
m = 0.44
Answer: B
Explanation: The density of a material affects the speed that a wave will be transmitted through it. In general, the denser the transparent material, the more slowly light travels through it. Glass is denser than air, so a light ray passing from air into glass slows down.
The answer is <span>A. 1/4 as much.
</span>
To calculate this, we will use Coulomb's Law:
F = k*Q1*Q2/r²
<span>where F is repulsive force, k is constant, Q is charge, r is distance between charges.</span>
k = 5.0 × 10⁹ N*m/C²
<span><span> <span> <span> <span> </span></span> </span></span> </span>
Let's take one example where:
Q1 = Q2 = 1.2 × 10⁻⁶ C²
r₁ = 0.5 m
So, F1 = k*Q1*Q2/r₁² = 5.0 × 10⁹ * 1.2 × 10⁻⁶ * 1.2 × 10⁻⁶ /0.5² = 12.96 × 10⁻²/0.25 = 51.84 × 10⁻² = 0.5184 ≈ 0.52
Let's now double r:
r₂ = 2r₁ = 2*0.5 = 1
And let's calculate force:
F2 = k*Q1*Q2/r₂² = 5.0 × 10⁹ * 1.2 × 10⁻⁶ * 1.2 × 10⁻⁶ /1² = 12.96 × 10⁻²/1 = 12.96 × 10⁻² = 0.1296 ≈ 0.13
And now, let's see how much is the second force (F2) differ from the first force (F1):
F2/F1 = 0.13/0.52 = 1/4
