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jeyben [28]
3 years ago
10

An ideal battery would produce an extraordinarily large current if "shorted" by connecting the positive and negative terminals w

ith a short wire of very low resistance. Real batteries do not. The current of a real battery is limited by the fact that the battery itself has resistance.
What is the resistance of a 9.0 V battery that produces a 17 A current when shorted by a wire of negligible resistance?

R=____
Physics
1 answer:
liubo4ka [24]3 years ago
6 0

Answer:

Resistance, R=0.529\ \Omega

Explanation:

Given that,

Voltage of the battery, V = 9 volts

Current produced in the circuit, I = 17 A

We need to find the resistance when shorted by a wire of negligible resistance. It is a case of Ohm's law. The voltage is given by :

V=IR

R=\dfrac{V}{I}

R=\dfrac{9\ V}{17\ A}

R=0.529\ \Omega

So, the resistance in the circuit is 0.529 ohms. Hence, this is the required solution.

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A 175-kg motorcycle goes around an unbanked turn of radius 75.4 m at a steady 112 km/h. Determine its acceleration?
Nuetrik [128]

Answer: 12.83 m/s^{2}

Explanation:

In this case we are talking about the centripetal acceleration a_{c}, which can be calculated by:

a_{c}=\frac{V^{2}}{r}

Where:

V=112 \frac{km}{h} \frac{1000 m}{1 km} \frac{1h}{3600 s}=31.11 m/s is the speed of the motorcycle

r=75.4 m is the radius of the path the motorcycle is going around

Solving:

a_{c}=\frac{(31.11 m.s)^{2}}{75.4 m}

Finally:

a_{c}=12.83 m/s^{2}

7 0
4 years ago
The most common type of lighting unit utilized in street lighting is:
Juli2301 [7.4K]
<span>Option C. The sodium vapor lamp is a gas discharge lamp that uses sodium vapor for the production of light. It is an efficient lighting source that provides lumens per watt and produces bright yellow. It has a monochromatic light that makes its applications are reduced. It is used in street lighting, streets, highways, etc.</span>
3 0
4 years ago
Can someone help?? 3/5
ycow [4]

Answer:

Yes to answer is 3/5 of what

8 0
3 years ago
A circular 10-turn coil with a radius of 5.0 cm carries a current of 5 A. It lies in the xy plane in a uniform magnetic field =
Tju [1.3M]

Answer:

U = – 0.12J

Explanation:

Given N = 10 turns, I = 5A, r = 5×10-²m

B^ = 0.05 T iˆ+ 0.3 T kˆ

Magnitude of the magnetic field vector B = √(0.05²+0.3²) = 0.304T

Area = πr² = π(5×10-²)² = 7.85×10-³m²

Magnetic moment μ = NIA

μ = 10×5×7.85×10-³ = 0.3925Am²

U = -μ•B = –0.3925×0.304 = –0.12J

The sign is negative because the magnetic moment is aligned with the magnetic field.

3 0
3 years ago
Evaluate the gravitational potential energy between two 5.00-kg spherical steel balls separated by a center-tocenter distance of
navik [9.2K]

Answer:

U = 8.30×10-⁹J

Explanation:

m1 = m2 = 5.00kg masses of the spheres

d = 15.0cm = 15×10-²m

r = 5.10cm = 5.10×10-²m

R = d + r = 15×10-² + 5.10×10-²

R = 20.10 ×10-²m = 0.201m

G = 6.67×10-¹¹Nm²/kg²

U = Gm1×m2/R = potential energybetween the spheres

U = 6.67×10-¹¹×5.00×5.00/0.201

U = 8.30×10-⁹J

7 0
3 years ago
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