All categories

4 years ago

A hair dryer is a pump for air. Do a battery and a Genecon act like pumps for charge?

Physics

2 answers:

lyudmila [28]4 years ago

8 0

Answer:

Explanation:

ohaa [14]4 years ago

7 0

Answer:

Yes

Explanation:

Genecon is hand operated power generator. So, it can be use to charge a battery.

You might be interested in

20.In case the conductor is a heating appliance, then this energy(w) is converted into heat(H) i.e

Scilla [17]

Answer:

not sure just need points

Explanation:

a+b+c

7 0

3 years ago

Which of the following represents units of geologic time in increasing order?

nordsb [41]

B. is the correct answer.

4 0

3 years ago

Read 2 more answers

How can we reduce the ripple factor of a bridge recitifier from 0.48 to 0.1 approximately ?

padilas [110]

U can try to use capacitor , the value of capacitor depends on circuit

ripple factors signifies the ac components, by def its ratio of rms value of ac component to value of dc component
so in order to reduce use of a capacitor which denies the sudden changes in voltage, which is the charracteristic of Ac signals

hope this helps

4 0

4 years ago

A projectile, fired with unknown initial velocity, lands 20sec later on side of hill, 3000m away horizontally and 450m verticall

lorasvet [3.4K]

Explanation:

Given:

t = 20 seconds

x = 3000 m

y = 450 m

a) To find the vertical component of the initial velocity $v_{0y}$ , we can use the equation

$y = v_{0y}t - \frac{1}{2}gt^2$

Solving for $v_{0y}$ ,

$v_{0y} = \dfrac{y + \frac{1}{2}gt^2}{t}$

$\:\:\:\:\:\:\:=\dfrac{(450\:\text{m}) + \frac{1}{2}(9.8\:\text{m/s}^2)(20\:\text{s})^2}{(20\:\text{s})}$

$\:\:\:\:\:\:\:=120.5\:\text{m/s}$

b) We can solve for the horizontal component of the velocity $v_{0x}$ as

$x = v_{0x}t \Rightarrow v_{0x} = \dfrac{x}{t} = \dfrac{3000\:\text{m}}{20\:\text{s}}$

$v_{0x} = 150\:\text{m/s}$

4 0

3 years ago

At resonance, what is impedance of a series RLC circuit? less than R It depends on many other considerations, such as the values

denis23 [38]

Answer:

at resonance impedence is equal to resistance and quality factor is dependent on R L AND C all

Explanation:

we know that for series RLC circuit impedance is given by

$Z=\sqrt{R^2+\left ( X_L-X_C \}right )^2$

but we know that at resonance $X_L=X_C$

putting $X_L=X_C$ in impedance formula , impedance will become

Z=R so at resonance impedance of series RLC is equal to resistance only

now quality factor of series resonance is given by

$Q=\frac{\omega L}{R}=\frac{1}{\omega CR}=\frac{1}{R}\sqrt{\frac{L}{C}}$ so from given expression it is clear that quality factor depends on R L and C

3 0

3 years ago