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babunello [35]
4 years ago
8

A hair dryer is a pump for air. Do a battery and a Genecon act like pumps for charge?

Physics
2 answers:
lyudmila [28]4 years ago
8 0

Answer:

No

Explanation:

ohaa [14]4 years ago
7 0

Answer:

Yes

Explanation:

Genecon is hand operated power generator. So, it can be use to charge a battery.

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Physical fitness involves the proper functioning of which body systems?
leva [86]
Respiratory
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Use the table below to answer the following questions. Substance Specific Heat (J/g•°C) water 4.179 aluminum 0.900 copper 0.385
lbvjy [14]

1. -8.78 \cdot 10^5 J

The energy lost by the water is given by:

Q=m C_s \Delta T

where

m = 3.0 kg = 3000 g is the mass of water

Cs = 4.179 J/g•°C is the specific heat

\Delta T=10.0C-80.0C=-70.0 C is the change in temperature

Substituting,

Q=(3000 g)(4.179 J/gC)(-70.0 C)=-8.78 \cdot 10^5 J

2. 3.24 \cdot 10^4 J

The energy added to the aluminium is given by:

Q=m C_s \Delta T

where

m = 0.30 kg = 300 g is the mass of aluminium

Cs = 0.900 J/g•°C is the specific heat

\Delta T=150.0 C-30.0C =120.0 C is the change in temperature

Substituting,

Q=(300 g)(0.900 J/gC)(120.0 C)=3.24 \cdot 10^4 J

3a. -5.6^{\circ}C

The temperature change of the water is given by

\Delta T=\frac{Q}{m C_s}

where

Q = -232 kJ=-2.32\cdot 10^5 J is the heat lost by the water

m=10.0 kg=10000 g is the mass of water

Cs = 4.179 J/g•°C is the specific heat

Substituting,

\Delta T=\frac{-2.32\cdot 10^5 J}{(10000g)(4.179 J/gC)}=5.6^{\circ}C

3b. +10.2^{\circ}C

The temperature change of the copper is given by

\Delta T=\frac{Q}{m C_s}

where

Q = 1.96 kJ=1960 is the heat added to the copper

m= 500 g is the mass of copper

Cs = 0.385 J/g•°C is the specific heat

Substituting,

\Delta T=\frac{1960 J}{(500g)(0.385 J/gC)}=10.2^{\circ}C

4. 42.9 g

The mass of the water sample is given by

m=\frac{Q}{C_S \Delta T}

where

Q=4300 J is the heat added

\Delta T=39 C-15 C=24C is the temperature change

Cs = 4.179 J/g•°C is the specific heat

Substituting,

m=\frac{4300 J}{(4.179 J/gC)(24 C)}=42.9 g

5. 115.5 J

The heat used to heat the copper is given by:

Q=m C_s \Delta T

where

m = 5.0 g is the mass of copper

Cs = 0.385 J/g•°C is the specific heat

\Delta T=80.0 C-20.0C =60.0 C is the change in temperature

Substituting,

Q=(5.0 g)(0.385 J/gC)(60.0 C)=115.5 J

6. 0.185 J/g•°C

The specific heat of iron is given by:

C_s = \frac{Q}{m \Delta T}

where

Q = -47 J is the heat released by the iron

m = 10.0 g is the mass of iron

\Delta T=25.0-50.4 C=-25.4 C is the change in temperature

Substituting,

C_s = \frac{-47 J}{(10.0 g)(-25.4 C)}=0.185 J/gC

8 0
4 years ago
Is the second largest planet, with an atmosphere of mainly hydrogen and helium, and rings of ice and rock particles
BartSMP [9]
The answer is Saturn. 


6 0
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How do I find net force when something has arrows all four directions with different N values for each?
Nimfa-mama [501]

In the vertical direction, take up to be positive and down to be negative. Then the net <u>vertical</u> force would be

5120 N - 4050 N = 1070 N

(it's positive, so the net vertical force is pointing upward)

In the horizontal direction, take right to be positive and left to be negative. Then the net <u>horizontal</u> force would be

950 N - 1520 N = -570 N

(negative means the net horizontal force points to the left)

So the net force on the balloon is the vector

<em>F</em> = (1070 N) <em>i</em> + (-570 N) <em>j</em>

(where <em>i</em> and <em>j</em> are the unit vectors in the horizontal and vertical directions, respectively)

The magnitude of the net force on the balloon is the magnitude of this vector:

<em>F</em> = √((1070 N)² + (-570 N)²)

<em>F</em> ≈ 1212 N

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3 years ago
How many electrons must be removed from a neutral object to leave a net charge of 0.500 μc?
blsea [12.9K]
<span>Net charge of the object = 0.500 ÎĽc
 The charge of electron = -1.602 x 10^-19 C
 Calculating the net change in the number of electrons = 0.5 x 10^-6 / -1.602 x 10^-19 = - 3.12 x 10^12
 The negative sign implies the number of electrons that needs to be removed that is 3.12 x 10^12</span>
4 0
4 years ago
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