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madreJ [45]
3 years ago
12

One of the asteroids, Ida, looks like an elongated potato. Surprisingly it has a tiny (compared to Ida) spherical moon! This moo

n called Dactyl has a mass of 4.20 × 10^16 kg, and a radius of 1.57 × 10^4 meters, according to Wikipedia. Ida has a radius of 3.14 x 10^4 meters.
Find the acceleration of gravity on the surface of this little moon.
Physics
1 answer:
Mashcka [7]3 years ago
8 0

Answer:

g = 0.0114 m/s²

Explanation:

The value of acceleration due to gravity on the surface of the moon can be given by the following formula:

g = \frac{Gm}{r^2}

where,

g = acceleration due to gravity on the surface of moon = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m = mass of moon = 4.2 x 10¹⁶ kg

r = radius of moon = 1.57 x 10⁴ m

Therefore,

g= \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(4.2\ x\ 10^{16}\ kg)}{(1.57\ x\ 10^4\ m)^2}

<u>g = 0.0114 m/s²</u>

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ball of mass 0.4 kg is attached to the end of a light stringand whirled in a vertical circle of radius R = 2.9 m abouta fixed po
Levart [38]

Answer:

6.046N

Explanation:

The net force exerted on the mass is the sum of tension force and the external force of gravity.

F_n_e_t=F_g+F_t

F_t is the tension force.F_g=9.8N/kg is the force of gravity.

F_n_e_t=ma_c=mv^2/r\\

where r is the rope's radius from the fixed point.

From the net force equation above:

F_t=F_n_e_t-F_g\\=mv^2/r-mg\\=0.4\times(8.5^2/2.9)-0.4\times9.8\\=6.046N

Hence the tension force is 6.046N

8 0
3 years ago
A person drives 70 km/h in 1 hour to the east, then 80 km/h for another hour to the east. What
andre [41]

Answer: The average velocity is 150 km/h

Explanation: 70+80=150

6 0
3 years ago
You run<br> completely around a 400m track in<br> 80s. What was your average velocity?
dalvyx [7]

Answer:

V=?

S=400m

t=80s

V=S/t

V=400/80

V=5m/sec

6 0
3 years ago
When exercising in the heat, which of the following hydration strategies is best for temperature regulation during an event (e.g
Olegator [25]

Answer:

Your question was incomplete so here is the complete question and answer.

Q. When exercising in the heat, which of the following hydration strategies is best for temperature regulation during an event (e.g., 10K race)

a) plain water

b) 5-7 percent glucose solution

c) Glucose polymer solution of 6-8 percent

d) There appears to be no difference among these different forms of hydration techniques relative to temperature regulation.

Ans. d) There appears to be no difference among these different forms of hydration techniques relative to temperature regulation.

Explanation:

Temperature Regulation is an important phenomenon for the person exposed to extreme hot conditions or weather. Exercising in hot conditions increase the body temperature. Greater and intense exercise, greater the production of heat. Then the heat dissipation takes place in the form of excessive sweating which results in dehydration. That was just the brief overview of temperature regulation. Above mentioned techniques are equally good hydration techniques so there is no difference at all. You can have a plain water or glucose solutions of above mentioned percentages.

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3 years ago
Increased________will lower viscosity
MrRa [10]
The answer is high temperatures
8 0
3 years ago
Read 2 more answers
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