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Yuliya22 [10]
3 years ago
11

So I need help with number 3 but if you want to help me with any other number 3 you can I wouldn’t mind

Mathematics
1 answer:
kondor19780726 [428]3 years ago
3 0

Answer:

3.) -x+4

4.)3/4x+3

5.)-3/5(x) -3

6.)-2x + 5

these are the "Slope intercept" forms of 3,4,5 and 6 you can learn to graph them as its hard for me to explain.

Step-by-step explanation:

3.) x+y=4, we want to write this in terms of y, so lets subtract x from both sides

y = -x+4 ----> this is in "slope intercept form" you can learn about this on "khan academy" as well.

4.) 3x-4y=-12 again we write in terms of y, subtract 3x from both sides.

-4y = -3x -12 then since we want y separately, we divide both sides by -4

y = 3/4(x) + 3 ------> if you didnt understand fully what i did to get to that, i divided everything by -4, and hopefully you know that a minus and a minus (multiplied or divided) will give a positive number.

5.) 3x+5y=-15 again we rewrite for y

5y = -3x - 15

y = -3/5(x) -3

6.) 2x+y = 5

y = -2x +5

the form in which y = whatever, is considered "slope-intercept form"

I cant really graph the points for you but watch this video, its very informative: https://www.khanacademy.org/math/algebra/two-var-linear-equations/graphing-slope-intercept-equations/v/graphing-a-line-in-slope-intercept-form  

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Simplify to create an equivalent expression. -k-(-8k+7)
const2013 [10]

Answer:

7k -7

Step-by-step explanation:

-k-(-8k+7)

Distribute the minus sign to all terms in the parentheses

-k--8k-7

Ad negative negative is a positive

-k + 8k -7

Combine like terms

7k -7

8 0
3 years ago
Roots of Quadratics 50 PTS!!!
noname [10]

The values of k for the different quadratic equation solutions are as follows

a  the equation 2x² - x + 3k = 0 has two distinct real roots

  • k < 1/24

b. the equation 5x² - 2x + (2k − 1) = 0 has equal roots

  • k = 3/5

ci the equation -x² + 3x + (k + 1) = 0 has real roots

  • k > -3.25

d the equation 3kx² - 3x + 2 = 0 has no real solutions

  • k < ± 1.633

<h3>How to solve quadratic equations to get different answers</h3>

Quadratic equations of the form ax² + bx + c = 0 is solved using the formula

-b+\frac{\sqrt{b^{2}-4ac } }{2a}     OR     -b-\frac{\sqrt{b^{2}-4ac } }{2a}

The equation b² - 4ac is called the discriminant and it is used as follows

To solve the equation and get two real roots: 2x² - x + 3k = 0

  • b² - 4ac > 0

substituting the values gives

(-1)² - 4 * 2 * 3k > 0

1 - 24k > 0

1 > 24k

divide through by coefficient of k

k < 1/24

To solve the equation and get equal roots: 5x² - 2x + (2k − 1) = 0

  • b² - 4ac = 0

substituting the values gives

(-2)² - 4 * 5 * (2k - 1) = 0

4 - 40k + 20 = 0

-40k = -24

divide through by coefficient of k

k = 3/5

To solve the equation and get real roots  -x² + 3x + (k + 1) = 0

  • b² - 4ac > 0

substituting the values gives  

(3)² - 4 * -1 * (k+1) > 0

9 + 4k + 4> 0

4k > -13

divide through by coefficient of k

k > -3.25

To solve the equation and get  no real solutions  3kx² - 3x + 2 = 0

  • b² - 4ac < 0

substituting the values gives  

(-3)² - 4 * 3k * 2 < 0

9 - 24k² > 0

9 > 24k²

divide through by coefficient of k²

k² < 24/9

k < ± 1.633

Learn more about roots of quadratic equations: brainly.com/question/26926523

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4 0
1 year ago
Read 2 more answers
Someone help me with this please
storchak [24]

Answer:

x = 114

Step-by-step explanation:

180 - 105 = 75

39 + 75 = x

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8 0
2 years ago
The midpoint of AB is M(-5,1). If the coordinates of A are (-4,-5), what are the coordinates of B?
Elenna [48]

<u>ANSWER:</u>

The midpoint of AB is M(-5,1). The coordinates of B are (-6, 7)

<u>SOLUTION: </u>

Given, the midpoint of AB is M(-5,1).  

The coordinates of A are (-4,-5),  

We need to find the coordinates of B.

We know that, mid-point formula for two points A(x_{1}, y_{1}) and B (x_{1}, y_{2}) is given by

M\left(x_{3}, y_{3}\right)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here, in our problem, \mathrm{x}_{3}=-5, \mathrm{y}_{3}=1, \mathrm{x}_{1}=-4 \text { and } \mathrm{y}_{1}=-5

Now, on substituting values in midpoint formula, we get

(-5,1)=\left(\frac{-4+x_{2}}{2}, \frac{-5+y_{2}}{2}\right)

On comparing, with the formula,

\frac{-4+x_{2}}{2}=-5 \text { and } \frac{-5+y_{2}}{2}=1

-4+\mathrm{x}_{2}=-10 \text { and }-5+\mathrm{y}_{2}=2

\mathrm{x}_{2}=-6 \text { and } \mathrm{y}_{2}=7

Hence, the coordinates of b are (-6, 7).

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3 years ago
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