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3 years ago

Can someone help me with this please and explain how they got the answer, please and thank you!

Mathematics

2 answers:

Tresset [83]3 years ago

5 0

The answer is 37 degrees. That is a 90 degree angle so if you subtract 90-53, you get 37.

Helga [31]3 years ago

5 0

See that little box in the angle? That means it is a right angle. A right angle is 90 degrees always. If the angle is split into two parts and one side is 53 degrees, the other side is the rest of the 90 degree angle. The two angles have to add together to make the 90 degree angle, so you just subtract 53 from 90 and get 37 degrees.

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If 6 bags of chocolate chips are needed to make 86 cookies, how many cookies can 8 bags chocolate chips make?

gulaghasi [49]

Answer:

114.666666667

Step-by-step explanation:

Step 1:

6/86 = 8/x Equation

Step 2:

6x = 688 Multiply

Step 3:

x = 688 ÷ 6 Divide

Answer:

x = 114.666666667

Hope This Helps :)

4 0

3 years ago

36-4c-3c=22 I don't understand how to solve for c

LiRa [457]

Subtract 36 from both sides making it: -4c-3c=-14
Now subtract -4c and 3c making it: -7c=-14
Now divide by -7 on both sides making it: c=2
There you go

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3 years ago

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A wallet that holds $25 contains the same number of $1 bills, $5 bills, and quarters. How many of each type of bill or coin does

Anastasy [175]

<span>The wallet contains 4 $1 bills, 4 $5 bills, and 4 quarters.

$1 </span>× 4 = $4
$5 × 4 = $20
$0.25 × 4 = $1
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3 0

3 years ago

Read 2 more answers

Help pls im being timed

Nitella [24]

The trigonometric ratios show that the angle FHE is 48.59°.

<h3>RIGHT TRIANGLE</h3>

A triangle is classified as a right triangle when it presents one of your angles equal to 90º. The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.

The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean Theorem.

The Pythagorean Theorem says: $(hypothenuse)^2=(leg_1)^2+(leg_2)^2$ . And the main trigonometric ratios are:

$sin(\alpha) =\frac{opposite \;leg }{hypotenuse} \\ \\ cos(\alpha) =\frac{adjacent\;leg }{hypotenuse} \\ \\ tan(\alpha) =\frac{sin(\alpha )}{cos(\alpha )}= \frac{opposite \;leg }{adjacent\;leg } \\ \\$

It is important to remember that the sum of internal angles for any triangle is 180°.

From the question, it is possible to see 2 right triangles (HGF and FHE).

You can find the hypotenuse of the triangle HGF from the trigonometric ratio: sen Θ

$sin45=\frac{opposite\; leg }{hypotenuse} =\frac{\sqrt8}{hypotenuse}\\ \\ \frac{\sqrt{2} }{2} =\frac{\sqrt{8} }{hypotenuse} \\ \\ \sqrt{2}*hypotenuse=2\sqrt{8} \\ \\ hypotenuse=\frac{2\sqrt{8} }{\sqrt{2}} =2\sqrt{4} =2*2=4$

The hypotenuse of triangle HGF is one of legs for the triangle FHE. The, you can find the angle FHE from the trigonometric ratio: tan β. Thus,

$sin \beta =\frac{opposite\; leg }{adjacent\; leg} =\frac{3}{4}\\ \\ sin \beta=\frac{3}{4}=0.84806\\ \\ arcsin\beta =48.59^{\circ \:}$

Learn more about trigonometric ratios here:

brainly.com/question/11967894

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