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FrozenT [24]
3 years ago
8

How to find q1 and q3

Mathematics
1 answer:
Aleksandr [31]3 years ago
3 0
What is the problem to begin with
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How long does it take the snail to crawl 82 inches? Enter your answer in a decimal number.
Sholpan [36]

Answer:

2827.5

Step-by-step explanation:

You have to divide 82 inches (distance) by the speed of the snail which is 0.029mph then you get the answer above.

8 0
3 years ago
What is the length of segment AB? <br> 5<br> 6<br> 8<br> 10
raketka [301]
Hi! So what this is asking for is how LONG the line is, not how tall. So you see B. It is on 0. And you go to A, it is on 6. Zero from 6 is 6. So 6 is your answer.
6 0
3 years ago
Please help me it is timed and i am running outta time
Westkost [7]

Answer:

In ∆RST and ∆XYZ

RS=YZ(S)

angle RST=angle XYZ(A)

ST=YZ(S)

hence ∆RST ≠~∆XYZ

7 0
3 years ago
Based on Pythagorean identities, which equation is true? A. Sin^2 theta -1= cos^2 theta B. Sec^2 theta-tan^2 theta= -1 C. -cos^2
Arturiano [62]

Answer:

D

Step-by-step explanation:

our basic Pythagorean identity is cos²(x) + sin²(x) = 1

we can derive the 2 other using the listed above.

1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)

1 + tan²(x) = sec²(x)

2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)

cot²(x) + 1 = csc²(x)

A. sin^2 theta -1= cos^2 theta

this is false

cos²(x) + sin²(x) = 1

isolating cos²(x)

cos²(x) = 1-sin²(x), not equal to sin²(x)-1

B. Sec^2 theta-tan^2 theta= -1

1 + tan²(x) = sec²(x)

sec²(x)-tan(x) = 1, not -1

false

C. -cos^2 theta-1= sin^2

cos²(x) + sin²(x) = 1

sin²(x) = 1-cos²(x), our 1 is positive not negative, so false

D. Cot^2 theta - csc^2 theta=-1

cot²(x) + 1 = csc²(x)

isolating 1

1 = csc²(x) - cot²(x)

multiplying both sides by -1

-1 = cot²(x) - csc²(x)

TRUE

3 0
3 years ago
Which statement is true for the equation 4n – 3 = 4n – 2 Select one: a. It has no solution. b. It has one solution. c. It has tw
oksian1 [2.3K]
4n-3=4n-2  subtract 4n from both sides

-3=-2 

Since -3!=-2, there is no solution.

So your answer is a.
7 0
3 years ago
Read 2 more answers
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