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Yuki888 [10]
3 years ago
6

A landlord owns 3 condominiums, a l-bedroom condo, a 2-bedroom condo, and a 3-

Mathematics
1 answer:
horrorfan [7]3 years ago
5 0

Answer:

1 bedroom = $280

2 bedroom = $400

3 bedroom = $560

Step-by-step explanation:

Given that :

Total rent received = 1240

Rent amount of 3 bedroom = 2 times rent of 1 bedroom

Let 1 bedroom = x

2 bedroom = y

3 bedroom = 2x

x + y + 2x = 1240

3x + y = 1240 ---(1)

Repair cost :

10% of x = 0.1x

20% of y = 0.2y

30% of 2x = 0.6x

0.1x + 0.2y + 0.6x = 276

0.7x + 0.2y = 276 - - - (2)

From (1)

y = 1240 - 3x

0.7x + 0.2(1240 - 3x) = 276

0.7x + 248 - 0.6x = 276

0.1x + 248 = 276

0.1x = 28

x = $280

1 bedroom = $280

3 bedroom = $280 * 2 = $560

2 bedroom = $1240 - $840 = $400

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oee [108]

Answer:

His gain percent is 20%

Step-by-step explanation:

In this question, we want to find the percentage gain of the business.

We need the following parameters;

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Using the values we have in the question;

The cost price will be;

13,600 + 400 = Rs 14,000

The selling price = Rs 16,800

Mathematically the percentage gain will be;

% gain = (selling price- cost price)/selling price * 100%

% gain = (16,800-14,000)/14,000 * 100/1

% gain = 2800/14,000 * 100/1 = 1/5 * 100/1 = 20%

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3 years ago
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solniwko [45]

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Step-by-step explanation:

4 0
3 years ago
What is 0.11/5.973 please show work
german

Answer:

  0.0184162062615101289...

Step-by-step explanation:

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This is a good problem for your calculator.

5 0
3 years ago
A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the
amm1812

Answer:

s(t)=(ln|7|+ln|2|)\,ft

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\

Integrating both sides w.r.to t

v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\

Using initial value

v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}

We have to calculate the distance covered in time interval [0,5], so:

\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft

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3 years ago
Find the area of the circle.<br> Use 3.14 for pi
Harman [31]
Answer:

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3 years ago
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