How to use the zero product property and factoring solve for X
1 answer:
Using the zero product property you can set each expression equal to 0 (or factor for some of them)
All you have to do is set them equal to zero and simplify to solve for x
a. (x+13)=0
x= -13
(x-7)=0
x=7
b. (2x+3)=0
x=-3/2
(3x-7)=0
x=7/3
c. x=0
(x-3)=0
x=3
d.
needs to be factored
factor out an x to get:
x(x-5) and set each equal to 0
x = 0
(x-5)=0
x=5
e.
also needs to be factored
(x-7)(x+5)=0
(x-7)=0 (x+5)=0
x=7 x=-5
f.
Also needs to be factored using the ac method:
(3x-1)=0
x=1/3
(x+5)=0
x=-5
I hope this helps! (if so, give brainliest please!!)
All you have to do is set them equal to zero and simplify to solve for x
a. (x+13)=0
x= -13
(x-7)=0
x=7
b. (2x+3)=0
x=-3/2
(3x-7)=0
x=7/3
c. x=0
(x-3)=0
x=3
d.
factor out an x to get:
x(x-5) and set each equal to 0
x = 0
(x-5)=0
x=5
e.
(x-7)(x+5)=0
(x-7)=0 (x+5)=0
x=7 x=-5
f.
Also needs to be factored using the ac method:
(3x-1)=0
x=1/3
(x+5)=0
x=-5
I hope this helps! (if so, give brainliest please!!)
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Answer:
5151.48 cms
Step-by-step explanation:
We have to:
1.68 m is 1680 cm.
Now the rope forms another right triangle. PQB, we can find the value of QB as follows:
tan (71 °) = PQ / QB
Solving:
QB = PQ / tan (71 °)
Replacing we have:
QB = 1680 / 2.9
QB = 579.31
Knowing this value we can find QA using similar triangles PQB and AQP, like this:
QA / PQ = PQ / QB
Solved:
QA = PQ ^ 2 / QB
Replacing:
QA = 1680 ^ 2 / 579.31
QA = 4872
Finally, knowing QA, we can calculate the one we want to know AP:
Sin (71 °) = AP / AB
But AB = QA + QB = 4872 + 579.31, therefore AB = 5451.31
Solved:
AP = Sin (71 °) * AB
Replacing:
AP = 0.945 * 5451.31
AP = 5151.48 cms
