3 years ago

How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?

2 answers:

5 0

No such triangle can exist. Any one side must be smaller than the sum of the other sides combined.

But $16>5+5=10$ , so the answer is B.

choli [55]3 years ago

4 0

Answer:

Step-by-step explanation:

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When you divide a number by a decimal less than 1, is the quotient less than or greater than the original number?

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Step-by-step explanation:

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3 years ago

What goes where. JdhshshHshxjancixd

valentina_108 [34]

Answer:

$\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }$

$\boxed { \frac{3}{5}y } \to \: \boxed {y - \frac{2}{5}y }$

Step-by-step explanation:

We need to simplify

$y + \frac{2}{5}y$

We collect LCM to get;

$\frac{5y + 2y}{5} = \frac{7y}{5}$

Therefore:

$\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }$

Also we need to simplify:

$y - \frac{2}{5}y$

We collect LCM to get;

$y - \frac{2}{5}y = \frac{5y - 2y}{5} = \frac{3}{5} y$

Therefore

$\boxed { \frac{3}{5}y } \to \: \boxed {y - \frac{2}{5}y }$

5 0

3 years ago

What is the solution to: <br> T/t-4=t+4/6

S_A_V [24]

$\frac{t}{t-4}= \frac{t+4}{6} \\ t \neq 4 \\ 6t= (t+4)(t-4) \\ 6t=t^2-16 \\ t^2-6t-16=0 \\ D=b^2-4ac=(-6)^2-4*1*(-16)=36+64=100 \\ t_{1,2}= \frac{-bб \sqrt{D} }{2a} \\ t_1= \frac{6-10}{2}=-2 \\ \ t_2= \frac{6+10}{2}=8$

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b≠a

.................

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