Answer:
Quadrants I and II.
O: (-2, 2)
N: (-2, 4)
M: (1, 4)
P: (1, 2)
Step-by-step explanation:
When rotating about the origin 90 degrees in a counterclockwise direction, focus on the coordinates of one point on the preimage at a time. So, the x-coordinate on the image will be the opposite of the y-coordinate of the preimage, and the y coordinate of the image will be the x-coordinate of the preimage. That sounds complicated so here is an example from the problem.
O is a point on the preimage. Its coordinates are (2, 2). To find the x-coordinate, take the opposite of the image's y-coordinate. The y-coordinate is 2, so it will be a -2 x-coordinate on the image. To find the y-coordinate on the image, take the x-coordinate of the preimage (O). The x-coordinate of O is 2, so the y-coordinate of the image will be 2. Combine those together and after a 90 degree counterclockwise rotation, you get a point of (-2, 2)
Answer:
Multiply 123 times 2 (246) and then divide that by 56 and add 7 to get your final answer.
-2<em>x</em> + 6<em>y</em> = -38
3<em>x</em> - 4<em>y</em> = 32
To solve by elimination, multiply the top equation by 3 and the bottom equation by 2.
3(-2<em>x</em> + 6<em>y</em> = -38) --> -6<em>x</em> + 18<em>y</em> = -114
2(3<em>x</em> - 4<em>y</em> = 32) --> 6<em>x</em> - 8<em>y</em> = 64
Add the equations.
-6<em>x </em>+ 18<em>y</em> = -114
6<em>x</em> - 8<em>y</em> = 64
+_____________
0 + 10<em>y</em> = -50
10<em>y</em> = -50
<em>y</em> = -5
Substitute -5 for y into one of the original equations to find x.
3<em>x</em> - 4<em>y</em> = 32
3<em>x</em> - 4(-5) = 32
3<em>x</em> + 20 = 32
3<em>x</em> = 12
<em>x</em> = 4
Check work by plugging the <em>x</em>- and <em>y</em>-values into both of the original equations.
-2<em>x</em> + 6<em>y</em> = -38
-2(4) + 6(-5) = -38
-8 - 30 = 38
38 = 38
3<em>x</em> - 4<em>y</em> = 32
3(4) - 4(-5) = 32
12 + 20 = 32
32 = 32
Answer:
<em>x</em> = 4 and <em>y</em> = -5; (4, -5).
Answer:
Its like... the divising of the shape
Step-by-step explanation:
