The weight of a person increase when the elevator is going up.
<h3>
Weight of the person in the elevator</h3>
The weight of the person in the elevator is calculated as follows;
<h3>When the person is going up</h3>
F = ma + mg
F = m(a + g)
where;
- a is acceleration of the person
- g is acceleration due to gravity
<h3>When the person is going down</h3>
F = mg - ma
F = m(g - a)
Thus, the weight of a person increase when the elevator is going up.
Learn more about weight here: brainly.com/question/2337612
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Answer:
q = 2.65 10⁻⁶ C
Explanation:
For this exercise we use Coulomb's law
F =
In this case they indicate that the load is of equal magnitude
q₁ = q₂ = q
the force is attractive because the signs of the charges are opposite
F = 
q = 
we calculate
q = 
q = 
Ra 7 10-12
q = 2.65 10⁻⁶ C
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