I’m not 100% but I was thinking A
Answer:
D. 0.9
Explanation:
Calculating minimum coefficient of static friction, we first resolve the forces (normal and frictional) acting on the vehicle at an angle to the horizontal into their x and y components. After this, we can now substitute the values of x and y components into equation of static friction. Diagrammatic illustration is attached.
Resolving into x component:
∑
------(1)
Resolving into y component:
∑
------(2)
Static frictional force,
μ
------(3)
substituting
from equation (1) and
from equation (2) into equation (3)
μ
μ
μ 
μ 
The angle the vehicles make with the horizontal α = 42°
μ ≥ tan 42°
μ ≥ 0.9
Answer:
a = 2 m/s2
Explanation:
we know from newtons 2nd law
F = ma.
we also know that from hookes law we have
F = kx
equate both value of force to get value of acceleration
kx = ma,
where,
k is spring constant = 8.0 N/m
x is maximum displacement 0.10 m
m is mass of object 0.40 kg
a = \frac{kx}{m}
= \frac{8 *0 .10}{0.40}
a = 2 m/s2
Answer:
let the speed of Allegra be x mph, then speed of Elliana is x+4 mph,
time to cover distance for Eliana is 2 hours, time to cover distance for Allegrais 2.5 hours,
since they both cover the same distance you have this,
distance (of Eliana) = distance (of Allegrais ),
distance=speed x time, so we have
speed (of Eliana) x time (of Eliana) = speed (of Allegra) x time (of Allegra),
2(x+4)=2.5x,
solve for x, then substitute back for speeds for Eliana and Allegra,
Eliana's speed = 16 + 4 = 20.
Allegra's speed = 16
Answer:
balanced?
Explanation:
because if it wasn't moving that means they are pulling at a similar strength