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Viefleur [7K]
3 years ago
8

In the diagram below, a heavy box is being lifted. What is the function of the pulley in this situation?

Physics
2 answers:
zepelin [54]3 years ago
8 0
I believe the correct answer from the choices listed above is option B. The function of the pulley in this situation is to change the direction of the input force. <span> The </span>pulley<span> simply turns a force in one direction into a force in another direction. Hope this answers the question. Have a nice day.</span>
goldenfox [79]3 years ago
6 0

Answer:

A

Explanation:

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Is platinum carbonate naturally occurring or human made?
skad [1K]

Answer:

no

Explanation:

Platinum is a noble metal. The concentrations of platinum in the soil, water and air are very minimal. ... Finally, a danger of platinum is that it can cause potentiation of the toxicity of other dangerous chemicals in the human body, such as selenium.

6 0
3 years ago
On Mars, where air resistance is negligible, an astronaut drops a rock from a cliff and notes that the rock falls about d meters
dimulka [17.4K]

Answer:

d_1 = 16 d

Explanation:

As we know that initial speed of the fall of the stone is ZERO

v_i = 0

also the acceleration due to gravity on Mars is g

so we have

d = v_i t + \frac{1}{2}gt^2

now we have

d = 0 + \frac{1}{2}g t^2

now if the same is dropped for 4t seconds of time

then again we will use above equation

d_1 = 0 + \frac{1}{2}g(4t)^2

d_1 = 16(\frac{1}{2}gt^2)

d_1 = 16 d

7 0
3 years ago
Read 2 more answers
A merry go round (mass of 200kg and radius 5m) is rotating so that the outside edge is moving 10m/s. A giant bug of 6kd at a dis
romanna [79]

Answer:

2 rad/s

Explanation:

For a rotating object, the linear velocity is given by

v=\omega r

where \omega is the angular velocity and r is the radius.

\omega=\dfrac{v}{r}

The edge has a linear velocity of 10 m/s and the radius at the edge is 5 m.

\omega=\dfrac{10 \text{ m/s}}{5 \text{ m}} = 2 \text{ rad/s}

8 0
3 years ago
A rigid tank contains 7 kg of an ideal gas at 5 atm and 30c. a valve is opened, and half of mass of the gas can escape. the fin
Readme [11.4K]
The equation of state for an ideal gas is
pV=nRT
where p is the gas pressure, V the volume, n the number of moles, R the gas constant and T the temperature.

The equation of state for the initial condition of the gas is
p_1 V_1 = n_1 R T_1 (1)
While the same equation for the final condition is
p_2 V_2 = n_2 R T_2 (2)

We know that in the final condition, half of the mass of the gas is escaped. This means that the final volume of the gas is half of the initial volume, and also that the final number of moles is half the initial number of moles, so we can write:
V_1 = 2 V_1
n_1 = 2 n_2
If we substitute these relationship inside (1), and we divide (1) by (2), we get
\frac{p_1}{p_2} = \frac{T_1}{T_2}

And since the initial temperature of the gas is T_1 = 30 C=303 K, we can find the final temperature of the gas:
T_2 = T_1  \frac{p_2}{p_1}=(303 K) \frac{1.5 atm}{5.0 atm}=90.9 K
6 0
3 years ago
Read 2 more answers
A box of mass 20kg is pulled up an inclined plane by a force of 285N. Given that the value of
lorasvet [3.4K]

Answer:

19.6 m/s

Explanation:

The parameters given are:

Mass M = 20 Kg

Force F = 285 N

Angle Ø = 30 degree

Time t = 4 seconds

Coefficient of friction = 0.72

At the plane, the weight of the box will be mgsinØ

Resolving forces at the plane, we will have:

MgsinØ + Fr = F

Where Fr = frictional force.

Fr = F - mgsinØ

Substitute all the parameters into the formula

Fr = 285 - 20 × 9.8 sin30

Fr = 285 - 98

Fr = 187 N

But for the box moving toward the top of the plane,

F - Fr = ma

Where a = V/t

Substitute all the parameters involved into the formula

285 - 187 = 20 ( V/4)

98 = 5V

V = 98/5

V = 19.6 m/s

Therefore, the speed with which the box is moving is 19.6 m/s

4 0
3 years ago
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