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julia-pushkina [17]
4 years ago
11

A cannonball is launched from the ground with 48279 Joules of kinetic energy. How much gravitational potential energy will the c

annonball hold when it has reached it's highest height? How do you know?
Physics
1 answer:
Mamont248 [21]4 years ago
6 0

When the cannonball is shot upwards, kinetic energy converts to gravitational potential energy (GPE).

As the ball rises, speed decreases and height increases.

So when the cannonball has reached its maximum height, all of the Kinetic energy has transferred into gravitational potential energy.

(Because at the max height, the cannonball for a brief moment has no velocity, and thus no kinetic energy)

So the GPE is 48279 Joules at it's maximum height.

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Rest energy is the energy a body has due to its position at rest.<br> True<br> False
OleMash [197]

Answer: The answer is True

8 0
3 years ago
Read 2 more answers
All power plants use fuel to supply energy that turns into:
AnnZ [28]

Answer: Electrical energy

Explanation:

A power plant is considering an industrial facility that has the ability to generate electricity from its primary energy.

There could be used one or more generator when it comes to power plants and their function is to convert mechanical energy into electrical energy in order to supply power to the electrical grid for other people that are needing electricity and more.

4 0
3 years ago
(a) A 70-kg person at rest has an oxygen consumption rate Qhum = 14.5 liter/h, 2% of which is supplied by diffusion through the
nevsk [136]

Answer:

(a) fd=1.7058\times 10^{-5}\ L.hr^{-1}.cm(b) [tex]r=26.008\ cm

Explanation:

(a)

  • Oxygen consumption rate of humans, Q_h=14.5\ L.hr^{-1}

area of human skin, A_h=1.7\ m^2

  • diffusion rate through skin of humans, d=2\%\ of\ Q_h
  • ∴d=\frac{2}{100} \times 14.5

d=0.29\ L.hr^{-1}

<u>Flux of diffusion rate, </u>

fd=\frac{d}{A}

fd=\frac{0.29}{17000}

fd=1.7058\times 10^{-5}\ L.hr^{-1}.cm(b)Surface area for a spherical animal:[tex]A=4.\pi.r^2

Diffusion flux rate for animal:

fd=\frac{14.5}{A}

1.7058\times 10^{-5}=\frac{14.5}{4.\pi.r^2}

r=26.008\ cm

4 0
4 years ago
SOS Two forces, one 5 N and the other 8 N, act on a single object. Which of the
Daniel [21]

If the two forces act in the same direction, their resultant is 13N .

If they act in opposite directions, their resultant is 3N .

These are the limits. The resultant is always between 3N and 13N.

So (B), (C), and (D) (3N, 10N, and 13N are possible.)

<em>(A)</em> 2N is not possible.

4 0
3 years ago
Suppose a small quantity of radon gas, which has a half-life of 3.8 days, is accidentally released into the air in a laboratory.
Daniel [21]

Answer:

1 day

Explanation:

Let the safe level = x

The current level = x + 0.2x = 1.2 x

Thus,

Half life = 3.8 days

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{3.8}\ days^{-1}

The rate constant, k = 0.1824 days⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

So,

\frac {[A_t]}{[A_0]} = x / 1.2 x = 0.8333

t = ?

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.8333=e^{-0.1824\times t}

t ≅ 1 day

<u>Lab must be vacated in 1 day.</u>

4 0
3 years ago
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