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aleksandr82 [10.1K]
3 years ago
7

Here is a graph of the movement of a car. What was the acceleration of this vehicle between 15 and 20 seconds? Show your work an

d your answers.

Physics
1 answer:
tekilochka [14]3 years ago
6 0
<span>-2.4 m/s^2 At 15 seconds, the velocity was 12 m/s, at 20 seconds, the velocity was 0 m/s. The graph shows a straight line between those 2 points, so the acceleration was uniform. So we have a velocity change of 0 m/s - 12 m/s = -12 m/s And a time i</span>
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A solid disk is rolling without slipping on a level surface at a constant speed of 2.50 m/s. (a) if the disk rolls up a 30.0o ra
AnnyKZ [126]

(a) By using the law of conservation of energy, the distance moved by the solid disk along the ramp is 0.96 m.

(b) The answer does not depend on the mass and radius of the disc as these values are canceled when the law of conservation of energy is applied.

What is the law of conservation of energy?

The law of conservation of energy states that the total energy of an isolated system is conserved.

The total initial energy Ei of the disc rolling down an inclined plane is given by the formula,

Ei=1/2*mv^2 + 1/2*Iω^2

where m is the mass of the disc, v is the velocity of the disc, I is the moment of inertia and ω is the angular velocity of the disc.

For a solid disc, I=1/2mr^2, and since it is rolling without slipping, the rolling velocity of the disc will be equal to its translational velocity, that is,

v=ωr or ω=v/r

So using ω=v/r and I=1/2mr^2, it can be written,

Ei=1/2*m(v)^2 + 1/2*(1/2mr^2)(v/r)^2

Ei=1/2*m(v)^2*(1+1/2*)

Ei=3/4*mv^2

If the height covered by the disc is h before stopping, then its final total  energy Ef will be equal to the potential energy, that is,

Ef=m*g*h

From the law of conservation of energy, it can be written,

Ei=Ef

3/4*mv^2=m*g*h

h=3v^2/(4g)

The length of the ramp is then given by the formula,

l=hcosecθ

where θ is the inclination angle. So

l= 3v^2/(4g)*cosecθ

Here g=9.8 m/s^2, v=2.5 m/s  and θ=30.0 degree. Using these values,

l= 3*(2.5 )^2/(4*9.8)*cosec( 30)

l= 0.96 m

Learn more about the law of conservation of energy,

brainly.com/question/14312374

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8 0
1 year ago
What is amplitude in a wave?
Alexxx [7]
The measurement of the wave trough
7 0
3 years ago
Two swimmers A and B, of weight 190 lb and 125 lb, respectively, are at diagonally opposite corners of a floating raft when they
Harrizon [31]

Answer:

a) 0.618 ft/s

b) 3.04 ft/s

Explanation:

<u>Givens:</u>

Weight of swimmer A W_{A} = 190 Ib.

Weight of swimmer B  W_{B}= 125 Ib.

Weight of the raft W_{R} = 300 Ib.  

Swimmer A walks toward swimmer B relative to the raft with a speed

V_{A/R}= 2 ft/s

<em>a)</em><em> Conservation of linear momentum </em>

m_{A} v_{A} +m_{B} v_{B} +m_{R} v_{R} =0..........(1)\\v_{A/R}=v_{A}  -v_{R}\\\v_{A}=v_{A/R}+v_{R}.................(2)

Since swimmer B does not move  

v_{B} =v_{R}...............(3)

Substitute from (2) and (3) into (1)

m_{A} (v_{A/R} +v_{R} )+m_{B} v_{R} +m_{R} v_{R}=0\\(m_{A}+m_{B}+m_{R})v_{R} =-m_{A}v_{A/R}\\v_{R}=\frac{-m_{A}v_{A/R}}{m_{A}+m_{B}+m_{R}} \\v_{R}=0.618ft/s

b) if the raft not to move v_{R}=0

from (2)

v_{A} =v_{A/R}

substitute in (1)

m_{A} v_{A/R} +m_{B} v_{B}+m_{R} (0)=0\\v_{B}=\frac{W_{A}v_{A/R}}{W_{B}} \\v_{B}=3.04ft/s

3 0
3 years ago
A ball of weight 400 N is placed on a smooth inclined plane of inclination 30o. To a point P on its circumference an inextensibl
sladkih [1.3K]
The Tension is 200N and the Normal force is
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Check the pic For solution !!

6 0
3 years ago
which term describes the energy an object has because of its motion? Potential Nuclear Kinetic Thermal
zysi [14]

Answer:

The answer is Kinetic Energy

Explanation:

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3 years ago
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