Answer:
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The point in the orbit of a planet, asteroid, or comet at which it is closest to the sun.
The angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.
<h3>What is the angular velocity of the propeller?</h3>
The angular velocity of the propeller in rad/s is given as follows:
1300 rev/min = 1300 * 2π/60 = 136.1 rad/s.
b. The linear velocity, v = radius * angular velocity
Linear velocity, v = 2.25/2 * 136.1
v = 153.1 m/s
c. Centripetal acceleration, ![a = \frac{v^{2}}{r}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bv%5E%7B2%7D%7D%7Br%7D)
![a = \frac{(153.1)^{2}}{1.125} = 20835.2\:ms^{2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%28153.1%29%5E%7B2%7D%7D%7B1.125%7D%20%3D%2020835.2%5C%3Ams%5E%7B2%7D)
Centripetal acceleration in terms of g; ![g = \frac{20835.2}{9.81} = 2123.8 g](https://tex.z-dn.net/?f=g%20%3D%20%5Cfrac%7B20835.2%7D%7B9.81%7D%20%3D%202123.8%20g)
Therefore, the angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.
Learn more about angular velocity and centripetal acceleration at: brainly.com/question/10703948
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Answer:
1 and 3
Explanation:
because they are going up from 0
Answer:
(a). The path length is 3.09 m at 30°.
(b). The path length is 188.4 m at 30 rad.
(c). The path length is 1111.5 m at 30 rev.
Explanation:
Given that,
Radius = 5.9 m
(a). Angle ![\theta=30°](https://tex.z-dn.net/?f=%5Ctheta%3D30%C2%B0)
We need to calculate the angle in radian
![\theta=30\times\dfrac{\pi}{180}](https://tex.z-dn.net/?f=%5Ctheta%3D30%5Ctimes%5Cdfrac%7B%5Cpi%7D%7B180%7D)
We need to calculate the path length
Using formula of path length
![Path\ length =angle\times radius](https://tex.z-dn.net/?f=Path%5C%20length%20%3Dangle%5Ctimes%20radius)
![Path\ length=0.523\times5.9](https://tex.z-dn.net/?f=Path%5C%20length%3D0.523%5Ctimes5.9)
![Path\ length =3.09\ m](https://tex.z-dn.net/?f=Path%5C%20length%20%3D3.09%5C%20m)
(b). Angle = 30 rad
We need to calculate the path length
![Path\ length=30\times5.9](https://tex.z-dn.net/?f=Path%5C%20length%3D30%5Ctimes5.9)
![Path\ length=177\ m](https://tex.z-dn.net/?f=Path%5C%20length%3D177%5C%20m)
(c). Angle = 30 rev
We need to calculate the angle in rad
![\theta=30\times2\pi](https://tex.z-dn.net/?f=%5Ctheta%3D30%5Ctimes2%5Cpi)
![\theta=188.4\ rad](https://tex.z-dn.net/?f=%5Ctheta%3D188.4%5C%20rad)
We need to calculate the path length
![Path\ length=188.4\times5.9](https://tex.z-dn.net/?f=Path%5C%20length%3D188.4%5Ctimes5.9)
![Path\ length =1111.56\ m](https://tex.z-dn.net/?f=Path%5C%20length%20%3D1111.56%5C%20m)
Hence, (a). The path length is 3.09 m at 30°.
(b). The path length is 188.4 m at 30 rad.
(c). The path length is 1111.5 m at 30 rev.