The total solar eclipse is the eclipse in which the Sun gets completely covered by the Moon and Solar Corona can be seen whereas in case of partial solar eclipse, the Sun is partially covered by the Moon and Solar Corona can’t be seen whereas, in case of annular solar eclipse, the moon is further away from the Earth than in case of Total solar eclipse.
<span>Corona is visible in case of the Total solar eclipse.</span>
Answer:

Explanation:
Un electrón tiene una carga negativa de
y la masa total es igual al producto del número de electrones y esa carga unitaria. El número de electrones se obtiene al dividir la carga total por la carga unitaria. (An electron has a negative charge of
and the total mass is equal to the product of the qunatity of electrons and such unit charge. The quantity of electrons is found by diving the total charge by the unit charge):



Haven't done one like this in awhile but I see no one is answering so I gave it a try. I think it's right but let me know if you see something fishy...
Answer:
1.98 x 10⁻⁷ F
Explanation:
w = width of the sheet = 5.9 cm = 0.059 m
L = length of the sheet = 5.6 m
Area of the sheet is given as
A = L w = (5.6) (0.059) = 0.3304 m²
d = distance between the sheets = 3.1 x 10⁻⁵ m
k = dielectric constant of teflon = 2.1
Capacitance is given as


C = 1.98 x 10⁻⁷ F
Answer:
The block has an acceleration of 
Explanation:
By means of Newton's second law it can be determine the acceleration of the block.
(1)
Where
represents the net force, m is the mass and a is the acceleration.
(2)
The forces present in x are
and
(the friction force):

Notice that
subtracts to
since it is at the opposite direction.

The forces present in y balance each other:

Therefore:
(3)
But
and writing (3) in terms of a it is get:

So the block has an acceleration of
.