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ikadub [295]
2 years ago
14

Carbon-14 emits beta radiation and decays with a half life of 5730 years. Assume you start with 2.5x10^15 grams of Carbon-14, ho

w many grams remain at
the end of 5 half lives?
A. 1.1x10^-10 g
B. 2.5x10^-10 g
C 1.3x10^-10 g
D. 5.0x10^-10 g
Chemistry
1 answer:
saveliy_v [14]2 years ago
3 0

The amount remaining at the end of 5 half-lives is 7.81×10¹³ g

From the question given above, the following data were obtained:

  • Half-life (t½) = 5730 years
  • Original amount (N₀) = 2.5×10¹⁵ g
  • Number of half-lives (n) = 5
  • Amount remaining (N) =?

The amount remaining can be obtained as follow:

N = 1/2ⁿ × N₀

N = 1/2⁵ × 2.5×10¹⁵

N = 1/32 × 2.5×10¹⁵

N = 0.03125 × 2.5×10¹⁵

N = 7.81×10¹³ g

Therefore, the amount remaining after 5 half-lives is 7.81×10¹³ g

Learn more about half-life: brainly.com/question/25783920

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Answer : The mass of hydrogen gas consumed will be, 4.5 grams

Explanation : Given,

Mass of N_2 = 21 g

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Molar mass of N_2 = 28 g/mole

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First we have to calculate the moles of N_2 and H_2.

\text{Moles of }N_2=\frac{\text{Mass of }N_2}{\text{Molar mass of }N_2}=\frac{21g}{28g/mole}=0.75moles

\text{Moles of }H_2=\frac{\text{Mass of }H_2}{\text{Molar mass of }H_2}=\frac{18g}{2g/mole}=9moles

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The balanced chemical reaction is,

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From the given balanced reaction, we conclude that

As, 1 mole of N_2 react with 3 moles of H_2

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The moles of hydrogen gas consumed = 2.25 mole

Now we have to calculate the mass of hydrogen gas consumed.

\text{Mass of }H_2=\text{Moles of }H_2\times \text{Molar mass of }H_2

\text{Mass of }H_2=(2.25mole)\times (2g/mole)=4.5g

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