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Elza [17]
3 years ago
11

An experiment requires 47.9 g g of ethylene glycol, a liquid whose density in SI units is 1114 kg/m3 k g / m 3 . Rather than wei

gh the sample on a balance, a chemist chooses to dispense the liquid using a graduated cylinder. What volume in milliliters of the liquid should be used?
Chemistry
1 answer:
Ad libitum [116K]3 years ago
4 0

Answer:

43 mL would be the volume in milliliters of the liquid that should be used

Explanation:

Ethylene glycol density = 1114 kg/m³

Mass of ethylene glycol density = 47.9 g

Let's convert the density to units of g/mL

1 cm³ = 1mL

1 kg = 1000 g

1m³ = 1000000 cm³

1114 kg . 1000 g / 1kg = 1114000 g

Ethylene glycol density = 1114000 g / 1000000 cm³ = 1.114 g/mL

Now we can apply the mass, to determine the volume in mL

Ethylene glycol density = Ehtylene glycol mass / Ethylene gylocl volume

1.114 g/mL = 47.9 g / Ethylene gylocl volume

Ethylene gylocl volume = 47.9 g / 1.114 g/mL → 42.99 mL ≅ 43mL

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If you put a straw into a glass of water, the straw looks to be bent, although nothing has physically happened to the straw. The term that describes this property of light is called refraction.

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Which electron configuration represents a potassium atom in excited state
Anestetic [448]

Answer: The electronic configuration of potassium atom in excited state is 1s^22s^22p^63s^22p^64s^04p^1

Explanation:

There are 2 states classified under energy levels:

1. Ground state: This is the lower energy state which is termed as stable state.

2. Excited state: This is the upper energy state and is termed as the unstable state. All the electrons which are present in this state always come back to the ground state.

Ground state electronic configuration of potassium (Z = 19) : 1s^22s^22p^63s^22p^64s^1

As, only 1 electron can freely move to upper state. Hence, the excited state electronic configuration of potassium will be: 1s^22s^22p^63s^22p^64s^04p^1

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3 years ago
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toms of elements at the top of a group on the periodic table are smaller than the atoms of elements at the bottom of the group.
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Answer:

Atoms of elements at the top of a group on the periodic table are smaller than the atoms of elements at the bottom of the group. ... The valence electrons of the larger atoms are farther from the nucleus and are easier to remove, so the metals near the bottom are more reactive than those at the top.

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FILL IN THE BLANKWORD BANK (can use more than once): less, increases, decreases, greaterNO2Cl(g)+NO(g)⇌NOCl(g)+NO2(g)1.Disturbin
Jlenok [28]

Explanation:

If we have the following reaction at equilibrium:

<em>                                           aA + bB ⇄ cC + dD</em>

where a, b, c, and d are the stoichiometric coefficients for the reacting species A, B,  C, and D. For the reaction at a particular temperature:

                       Kc=([C]^c *[D]^d)/([A]^a *[B]^b)

where Kc is the equilibrium constant, which holds that <em>for a reversible reaction at equilibrium  and a constant temperature, a certain ratio of reactant and product concentrations has  a constant value, Kc</em> (the equilibrium constant). Note that although the concentrations  may vary, as long as the reaction in in equilibrium and temperatura don't change, the value of <u>K remains constant.</u>

For reactions that have not reached equilibrium, we obtain the reaction quotient (Qc), instead of the equilibrium  constant <u>by substituting the initial concentrations into the equilibrium constant expression.</u>

                        Qc=([Co]^c *[Do]^d)/([Ao]^a *[Bo]^b)

To determine the direction in wich the net reaction will proceed to reach equilibrium, que compare the values of Qc and Kc.

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Solution:

We have the following reaction:

                             NO2Cl(g)+NO(g)⇌NOCl(g)+NO2(g)

So:

Kc=([NOCl]^1*[NO2]^1)/([NO2Cl]^1 *[NO]^1)

     =([NOCl][NO2])/([NO2Cl][NO])  

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2. To reach a new state of equilibrium (<em>where Qc = Kc</em>), Qc therefore  increases wich means that the denominator of the expression for Qc  decreases <em>(in order to increase the denominator as mention above).</em>

3. To accomplish this, the concentration of reageants decreases <em>(reagents are being consumed), </em>and the concentration of prodcuts increases <em>(products are being formed).</em>

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