The number of valence electron in sodium is 1 and that in chlorine are 7. In order to complete the octet (8 electrons in outermost shell) sodium can give its valence electron to an atom with more electronegativity. Here, chlorine is more electronegative than sodium, due to 7 valence electrons it required one more electron to complete its octet.
Therefore, chlorine can take 1 valence electron of sodium to form ionic bond. In the ionic compound so formed, both sodium and chlorine have complete octets. In aqueous solution they exist as 
and 
ions, the positive charge on sodium indicates that it donates its one electron and negative charge on chlorine indicates that it accepts an electron.
All this happen due to difference in electronegativity of sodium and chlorine (chlorine is more electronegative than sodium).
Matter - anything with mass and occupies space
accuracy - an indication of how close a measurement is to the correct result
precision - the degree to which a measurement can be replicated
meniscus - the curved top surface of a liquid column
volume - spaced occupied measured in cubic units
density - mass of an object per unit volume
Answer:
Ea = 177x10³ J/mol
ko = 
J/mol
Explanation:
The specific reaction rate can be calculated by Arrhenius equation:
Where k0 is a constant, Ea is the activation energy, R is the gas constant, and T the temperature in Kelvin.
k depends on the temperature, so, we can divide the k of two different temperatures:
Applying natural logathim in both sides of the equations:
ln(k1/k2) = Ea/RT2 - Ea/RT1
ln(k1/k2) = (Ea/R)x(1/T2 - 1/T1)
R = 8.314 J/mol.K
ln(2.46/47.5) = (Ea/8.314)x(1/528 - 1/492)
ln(0.052) = (Ea/8.314)x(-1.38x
-1.67x
xEa = -2.95
Ea = 177x10³ J/mol
To find ko, we just need to substitute Ea in one of the specific reaction rate equation:
ko = J/mol
0.636 moles of CO2 or using significant figures the answer would be 0.64 moles of CO2
How many mL of a 0.10 M NaOH solution are needed to neutralize 15 mL of 0.20 M H3PO4?
5.0 (328)
Ph. D. in organic chemistry with 6+ years of teaching experi..
Write down the balanced reaction first
3NaOH + H3PO4 makes Na3PO4 + 3H2O
Given 0.10M NaOH (0.10mol/lit NaOH)
0.2M H3PO4 ( 0.2 mol/lit H3PO4)
15 ml of H3PO4 or 0.015 lit of H3PO4
Find volume of NaOH needed to neutralize the solution
Relate moles of H3PO4 with the moles of NaOH with the helps of coefficients in front of NaOH and H3PO4 seen in balanced equations.
moles ↔ Litre use definition of molarity (moles/litrs)
Start with what is given for H3PO4
0.015 lit of H3PO4 x 0.2 moles of H3PO4 / lit of H3PO4 x 3 moles of NaOH/1 mole of H3PO4 x lit of NaOH/0.1 mol of NaOH = 0.09 lit or 90 ml.
The same colors in above equations cancel our leaving lit of NaOH as final answer.
