Geometry...halp QwQ......

What is the median value of the data set shown on the line plot?<br> Enter your answer in the box.

aksik [14]

Answer:

please add the picture for us to see.

Step-by-step explanation:

5 0

2 years ago

Two angles in a triangle have measures of 23 and 98 what is the third measure of the third angle

Feliz [49]

Answer:

59

Step-by-step explanation:

As far as I know every triangle has to equal 180°

So if you add 98+23 you would get 121

subtract that from 180 and get 59

Hope this helps!

5 0

3 years ago

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Find the minimum sample size needed to estimate the percentage of Democrats who have a sibling. Use a 0.1 margin of error, use a

Brums [2.3K]

Answer:

The minimum sample size is $n =135$

Step-by-step explanation:

From the question we are told that

The confidence interval is $( lower \ limit = \ 0.44,\ \ \ upper \ limit = \ 0.51)$

The margin of error is $E = 0.1$

Generally the sample proportion can be mathematically evaluated as

$\r p = \frac{ upper \ limit + lower \ limit }{2}$

$\r p = \frac{ 0.51 + 0.44}{2}$

$\r p = 0.475$

Given that the confidence level is 98% then the level of significance can be mathematically evaluated as

$\alpha = 100 - 98$

$\alpha = 2\%$

$\alpha =0.02$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

The value is

$Z_{\frac{\alpha }{2} } = 2.33$

Generally the minimum sample size is evaluated as

$n =[ \frac { Z_{\frac{\alpha }{2} }}{E} ]^2 * \r p (1- \r p )$

$n =[ \frac { 2.33}{0.1} ]^2 * 0.475(1- 0.475 )$

$n =135$

6 0

3 years ago

I need help with this math qustoin 2(2+455×330)÷3×2 and anyone bored

____ [38]

Solve what is in the parenthesis first. Then multiply that by 2 then divide that by 3 then multiply that by 2. know your order of operations.

6 0

3 years ago

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Assume the heights in a female population are normally distributed with mean 65.7 inches and standard deviation 3.2 inches. Then

siniylev [52]

Answer:

0.620

Step-by-step explanation:

We know that 1 feet = 12 inches, so, 5 feet is equivalent to 60 inches. Then, we are looking for the probability that a typical female from this population is between 60 inches and 67 inches. We know that

$\mu$ = 65.7 inches and

$\sigma$ = 3.2 inches

and the normal density function for this mean and standard deviation is

$\frac{1}{\sqrt{2\pi } 3.2}exp[-\frac{(x-65.7)^{2}}{2(3.2)^{2}} ]$

The probability we are looking for is given by

$\int\limits^{67}_{60} {\frac{1}{\sqrt{2\pi } 3.2}exp[-\frac{(x-65.7)^{2}}{2(3.2)^{2}} ] } \, dx =0.620$

You can use a computer to calculate this integral. You can use the following instruction in the R statistical programming language

pnorm(67, 65.7, 3.2)-pnorm(60, 65.7, 3.2)

7 0

3 years ago