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uranmaximum [27]
3 years ago
8

PLZ HELP WILL GIVE BRAINLISET IF RIGHT!!!

Mathematics
1 answer:
Irina-Kira [14]3 years ago
5 0

Answer:

72.5mph

Step-by-step explanation:

There is an easy way to work this. Divide the miles he drove by 2 so that you know how much he drove in 1/5 hours.

29/2= 14.5miles driven in 1/5 hours

Now, just multiply that number by 5 so that you know how many miles he drove in 5/5 hours (one full hour).

14.5*5= 72.5miles

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Answer:

4x^2-20x+25

Step-by-step explanation:

(2x-5)^{2} \\(2x)^2+2(2x)(-5)+(-5)^2\\4x^2-20x+25

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Inverse function. sketch the graph of each function.​
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I cant see picture

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8 0
3 years ago
Mike pays $20 per hour for algebra tutoring. The equation y = 20x relates the cost of tutoring (y) to the number of hours (x) he
kotykmax [81]

The unit rate in the equation is 20.

Option C) is the correct answer.

<u>Step-by-step explanation</u>:

Step 1 :

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8 0
3 years ago
A running circuit is in the shape of a triangle with lengths of 6km, 6.5km and 7km. What are the sizes of the angles (in minutes
Rudik [331]

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}. The <em>measures</em> of the internal <u>angles</u> of the <u>triangle</u> given in the question are A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to 180^{o}.

Considering the given question, let the <u>sides</u> of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.

Apply the <em>Cosine rule</em> to have:

c^{2} = a^{2} + b^{2} - 2ab Cos C

So that;

7^{2} = 6^{2} + (6.5)^{2} - 2(6 * 6.5) Cos C

49 = 36 + 42.25 - 78Cos C

78 Cos C = 78.25 - 49

               = 29.25

Cos C = \frac{29.25}{78}

         = 0.375

C = Cos^{-1} 0.375

   = 67.9757

C = 68^{o}

Apply the <em>Sine rule</em> to determine the <u>value</u> of B,

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{6.5}{Sin B} = \frac{7}{Sin 68}

SIn B = \frac{6.5 *Sin 68}{7}

         = 0.861

B = Sin^{-1} 0.861

   = 59.43

B = 59.4^{o}

Thus to determine the value of A, we have;

A + B + C = 180^{o}

A + 59.4^{o} + 68^{o} = 180^{o}

A = 180^{o} - 127.4

  = 52.6

A = 52.6^{o}

Therefore the <u>sizes</u> of the <em>internal angles</em> of the triangle are: A = 52.6^{o}, B = 59.4^{o}, and C = 68^{o}.

For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814

#SPJ1

8 0
2 years ago
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