The compromise of 1877 for apex :) hope this helps
Each chromosome has 46 in mitosis whereas meiosis has 23 pairs from each gametes (egg cells and sperm) from the parents which are called daughter cells so the answer is 23 and 23 one from the mother and the other from the father
<h2>Frequency of allele </h2>
Explanation:
Hardy Weinberg Equilibrium is used to calculate the allelic as well as genotypic frequency
Allelic frequency of dominant and recessive allele is represented by p and q respectively whereas genotypic frequency of dominant genotype is represented by
and
respectively
Given:
H allele (p) = hairy heffalump (dominant)
h allele (q) = hairless heffalump (recessive)
36% of heffalump population is hairless represents the % of recessive genotype, hh (
) =36%
Calculation of frequency of the h allele (q) :
Frequency of genotype hh (
) will be: 36/100=0.36 or 0.6*0.6
Frequency of h allele (q) will be 0.6
B.
Both processes have a growth period called interphase, in which a cell replicates its genetic material and organelles in preparation for division. The two cells that result after meiosis I enter meiosis II very quickly, during the brief interphase period, no further DNA replication takes place.
C.
A. True