[ H₃O⁺] = 10 ^- pH
[ H₃O⁺] = 10 ^ (- 5.75 )
[H₃O⁺] = 1.778x10⁻⁶ M
Kw = [ H₃O⁺] x [ OH⁻]
1x10⁻¹⁴ = 1.778x10⁻⁶ x [OH⁻]
[OH⁻] = 1x10⁻¹⁴ / 1.778x10⁻⁶
[OH⁻] = 5.62x10⁻⁹ M
hope this helps!
Option D
The car is accelerating, because if it were at rest you wouldn't see the line, and if the car was going at constant speed (forwards or backwards) then the line would be straight.
<em>Have a luvely day!</em>
1996,1997,1999,1998,2000 that will be 4
The particals in a physical change alwayd stay the same, but for a chemical change that is the only time they will change. Not during a physical change
To find the experimental value I believe we add up all the temperatures found by each trial and divide by the number of trials
When added up and divided up this is 50.7 C
Then we continue with accepted value minus experimental value over accepted
53.0 - 50.7 / 53.0 x 100
4.3% percent error
