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natulia [17]
3 years ago
8

Which statement is true about both a solid and a gas? A. They both fill a container. B. The both have defined shapes in any spac

e. C. The atoms of both are moving. D. There is never any motion in either.        PLEASEEE HELP PLEASEEEEEEEEE
Chemistry
2 answers:
hram777 [196]3 years ago
5 0

Answer: Option (C) is the correct answer.

Explanation:

In a solid, molecules are held together by strong intermolecular forces of attraction. As a result, they are unable to move from their initial place but they can vibrate at their mean position.  

Hence, in solid substances the molecules have low kinetic energy and they have fixed shape and volume.

In gases, the molecules are held by weak Vander waal forces. Hence, they have high kinetic energy due to which they move rapidly from one place to another leading to more number of collisions.  

Hence, gases are able to expand more rapidly as compared to liquids and solids.

Thus, we can conclude that the statement atoms of both are moving, is true about both a solid and a gas.

Fiesta28 [93]3 years ago
4 0
In any state of matter there is always motion in the atoms. So the answer would be C even though solids are together and gases atoms are spread out
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Calculate the mass defect for the formation of phosphorus-31. The mass of a phosphorus-31 nucleus is 30.973765 amu. The masses o
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<u>Answer:</u> The mass defect for the formation of phosphorus-31 is 0.27399

<u>Explanation:</u>

Mass defect is defined as the difference in the mass of an isotope and its mass number.

The equation used to calculate mass defect follows:

\Delta m=[(n_p\times m_p)+(n_n\times m_n)]-M

where,

n_p = number of protons

m_p = mass of one proton

n_n = number of neutrons

m_n = mass of one neutron

M = mass number of element

We are given:

An isotope of phosphorus which is _{15}^{31}\textrm{P}

Number of protons = atomic number = 15

Number of neutrons = Mass number - atomic number = 31 - 15 = 16

Mass of proton = 1.00728 amu

Mass of neutron = 1.00866 amu

Mass number of phosphorus = 30.973765 amu

Putting values in above equation, we get:

\Delta m=[(15\times 1.00728)+(16\times 1.00866)]-30.973765\\\\\Delta m=0.27399

Hence, the mass defect for the formation of phosphorus-31 is 0.27399

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