What is the average rate of change for this function for the interval from x=3 to x=5?

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

4 0

Answer:

A. 49

Step-by-step explanation:

The average rate of change for the interval ranging from x = 3 to x = 5 for the given function represented in the table above can be calculated using:

$Average rate of change = \frac{f(x2) - f(x1)}{x2 - x1}$

x2 = 5

x1 = 3

f(x2) = f(5) = 125

f(x1) = f(3) = 27

Thus,

$Average rate of change = \frac{125 - 27}{5 - 3}$

$= \frac{98}{2}$

Average rate of change = 49

Average rate of change of the given table values representing an exponential function is A. 49.

You might be interested in

When the smaller of two consecutive integers is added to four times the larger, the result is 49. Find the integers.

ryzh [129]

$4(n+1)+n=49\\
4n+4+n=49\\
5n=45\\
n=9\\
n+1=10
$

These numbers are 9 and 10.

8 0

3 years ago

Select the quadratic equation that has roots x=8 and x=-5

stellarik [79]

Step-by-step explanation:

Since, x=8 and x=-5 are the roots.

Therefore, (x - 8) & (x - 5) will be factors.

Hence, required quadratic equation can be given as:

$(x - 8)(x - 5) =0 \\ \\ \therefore {x}^{2} + ( - 8 - 5) x+ ( - 8) \times ( - 5) = 0 \\ \\ \therefore {x}^{2} + ( - 13) x+ 40= 0 \\ \\ \huge \red{ \boxed{ \therefore {x}^{2} - 13x+ 40= 0 }} \\ is \: the \: required \: quadratic \: equation.$