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Amanda [17]
2 years ago
13

On the school playground, the slide is 12 feet due west of the tire swing and 16 feet due south of the monkey bars. What is the

distance between the tire swing and the monkey bars?

Mathematics
1 answer:
ikadub [295]2 years ago
3 0

Answer:

The distance between the tire swing and the monkey bars is 20 feet.

Step-by-step explanation:

We have drawn the diagram four reference.

Given:

the slide is 12 feet due west of the tire swing

So according the diagram;

TS = 12 feet

Also Given:

slide is 16 feet due south of the monkey bars.

So according the diagram;

MS = 16 feet

We need to find the distance between the tire swing and the monkey bars.

according to diagram we need to find the MT.

Solution:

assuming it to be right angle triangle with right angle at S.

we have;

In Δ MTS;

\angle S = 90\°

TS = 12 feet

MS = 16 feet

Now applying Pythagoras theorem which states that;

"Sum of the square of the two side of the triangle is equal to square of the hypotenuse."

framing in equation form we get;

MT^2=TS^2+MS^2

Substituting the values we get;

MT^2= 12^2+16^2= 144+256 =400

Taking square root on both side we get;

\sqrt{MT^2}=\sqrt{400} \\ \\MT =20\ ft

Hence the distance between the tire swing and the monkey bars is 20 feet.

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KIM [24]

Answer: Period = 2 seconds

Graph is shown below

========================================================

Explanation:

1 minute = 60 seconds

We have 30 revolutions every 60 seconds, so we can write the ratio

30 rev: 60 sec

Divide both parts by 30 to turn that "30 rev" into "1 rev"

30 rev: 60 sec

30/30 rev: 60/30 sec

1 rev : 2 sec

This tells us that each full revolution takes 2 seconds. This is the period of the ferris wheel. The period is the length of each cycle.

The cyclic or periodic nature of this motion heavily implies we'll be dealing with a sine or cosine function of some kind. Let's go with sine.

Side note: cosine is really a sine function in disguise (it's just a phase shifted version of it).

---------------------

The general sine curve equation is

y = A*sin(B(x-C)) + D

where

  • |A| = amplitude
  • B = 2pi/T with T being the period
  • C handles phase shifts (left and right shifting)
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---------------------

The wheel is 10 feet in diameter, so 10/2 = 5 is the radius. This is also the amplitude because it is the distance from the midline to either the highest point (10 ft) or lowest point (0 ft). So A = 5.

Since T = 2 is the period, this means,

B = 2pi/T

B = 2pi/2

B = pi

We don't have any phase shifts to worry about so C = 0.

The midline is D = 5 since this is halfway up

----------------------

Putting all the pieces together, we get this sine equation

y = A*sin(B(x-C)) + D

y = 5*sin(pi*(x-0)) + 5

y = 5*sin(pi*x) + 5

The graph is shown below.

x = time in seconds, y = height of the seat

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Answer:

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2. Jamie is about 56 meters away from Cameron.

3. Arthur is closer to Cameron.

Step-by-step explanation:

We have been given the locations of Cameron (70,10), Arthur (20,30) and Jamie (45,60) on the the grid in meters.

1. To find the distances of Arthur and Jamie from Cameron we will use distance formula.

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Therefore, the distance Arthur is about 54 meters away from​ Cameron.

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\text{Distance between Cameron and Jamie}=\sqrt{3125}

\text{Distance between Cameron and Jamie}=55.9016994374947424\approx 56

Therefore, Jamie is about 56 meters away from​ Cameron.

3. We can see that 56 is greater than 54, therefore, Arthur is closer to Cameron.


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