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3 years ago

Find the area of the shape

Mathematics

1 answer:

Tamiku [17]3 years ago

6 0

Answer:

1296 sorry if im wrong

Step-by-step explanation:

:):):):):):):):):):):):):):):):):):):):):):):)

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What is the value of a

Diano4ka-milaya [45]

Answer: Multiplying 3x and -x we obtain A= -3x^2

8 0

3 years ago

You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b

Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

$\mathbf{x = 100\ m}$

$\mathbf{\frac{dy}{dt} = 2\ ms^{-1}}$ ---- the rate

$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

$\mathbf{\tan(\theta) = \frac{y}{x}}$

Substitute 100 for x

$\mathbf{y = 100\tan(\theta) }$

$\mathbf{\tan(\theta) = \frac{y}{100}}$

Differentiate both sides with respect to time (t)

$\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}$

Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

$\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

Divide both sides by 2

$\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }$

$\mathbf{ \frac{d\theta}{dt} = 0.01 }$

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

8 0

2 years ago

12. (r - 5)3 + r2 ifr= -3 and s= -4

Natasha2012 [34]

Answer:

-503

Step-by-step explanation:

the statement tell us:

(r - 5)^3 + r^2

r= -3

so we have:

(-3 - 5)^3 + (-3)^2

(-8)^3 + 9

-512+9 = -503

6 0

3 years ago

3. A submarine dives at an

Vesna [10]

Answer:

The height of deepness of submarine is 424.1 feet

Step-by-step explanation:

Given as :

The angle at which submarine drives of the surface of water = Ф = 13°

The speed at which submarine travel = s = 760 feet per minute

Let The height of deepness of submarine = h feet

The time taken to reach that deepness = t = 5 minutes

<u>According to question</u>

The height of deepness of submarine = $\dfrac{\textrm speed}{\textrm time}$

i.e h × cos(90 - Ф) = $\dfrac{s}{t}$

Or, h × Sin(Ф) = $\dfrac{\textrm 760 feet per min}{8 min}$

Or, h × Sin(13°) = 95 feet

Or, h × 0.224 = 95 feet

∴ h = $\dfrac{95}{0.224}$

i.e h = 424.10 feet

So, The height of deepness of submarine = h = 424.10 feet

Hence, The height of deepness of submarine is 424.1 feet Answer

8 0

3 years ago

What is the answer to this −8(9r−1)−9(−8r+2)

Nitella [24]

Answer:

-10

Step-by-step explanation:

-72r+8+72r-18

-10

7 0

3 years ago

Read 2 more answers