Find the area of the shape

Mathematics

1 answer:

Tamiku [17]2 years ago

6 0

Answer:

1296 sorry if im wrong

Step-by-step explanation:

:):):):):):):):):):):):):):):):):):):):):):):)

You might be interested in

Solve the equation using the quadratic formula : x^2-10x+25=18

Sever21 [200]

$x^2-10x+25=18 \\ \\x^2-10x+25-18 = 0\\ \\ x^2-10x+ 7 =0 \\ \\a=1 , b = -10 , c= 7 \\ \\ \Delta = b^{2}-4ac = (-10)^{2}-4*1*7=100-28 = 72 \\ \\\sqrt{\Delta }=\sqrt{72}= \sqrt{2*36} =\sqrt{36}*\sqrt{2} =6\sqrt{2}$

$x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{10- 6\sqrt{2}}{2}=\frac{2(5-3\sqrt{2})}{2}= 5-3\sqrt{2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{10+ 6\sqrt{2}}{2}=\frac{2(5+3\sqrt{2})}{2}= 5+3\sqrt{2}$

$Answer : \ x= 5-3\sqrt{2} \ \ or \ \ x = 5+3\sqrt{2}$

8 0

3 years ago

Need answer to this math problem

Elis [28]

The slope of this line is the difference of the y values divided by the difference of the x values. Solving this give 4/-3. Then, you already know the b in y = mx+b, which is 2, because you already have the value (0, 2). So, the answer is y = $-\frac{4}{3}$ x + 2