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3 years ago

The dot plot shows the number of visitors. Deter the median of the data set

2 answers:

5 0

Do you have an attachment for this problem? You can find the median by putting the numbers in order and finding out which is the middle number. If there are two numbers in the middle, add them, and divide it by 2, and you can find your answer.

strojnjashka [21]3 years ago

4 0

Where is the dot plot? Otherwise, the median is determined by finding out what is the middle number.

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Consider the one-sided confidence interval expressions for the mean of a normal population. Round your answers to 2 decimal plac

ser-zykov [4K]

Answer: a) 0.84 b) 0.67 c) 1.28

Step-by-step explanation:

Using the standard normal distribution table for z-value , we have

(a) The value of $z_{\alpha}$ would result in a 80% one-sided confidence interval : $z_{(1-0.80)}=z_{0.20}=0.8416\approx0.84$

(b) The value of $z_{\alpha}$ would result in a 85% one-sided confidence interval : $z_{(1-0.85)}=z_{0.25}=0.6744897\approx0.67$

(c) The value of $z_{\alpha}$ would result in a 90% one-sided confidence interval : $z_{(1-0.90)}=z_{0.10}=1.2815515\approx1.28$

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3 years ago

12=15(z−51) What is Z

professor190 [17]

Answer:

51.8

Step-by-step explanation:

Multiply 15 by z and -51 which would equal (15z-765).

Add 765 to 12 and that equals 777

Divide 777 by 15 which would equal 51.8

4 0

3 years ago

(18x3-3x2++x-1)/(x2-4)

Gwar [14]

18x^5-3x^4+x^3-x^2-72x^3+12x^2-4x+4, and then you will combine like terms to be :

18x^5-3x^4-71x^3+11x^2-4x+4

4 0

3 years ago

Read 2 more answers

Suppose that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage

Zigmanuir [339]

Answer:

We conclude that the percentage of blue candies is equal to 29%.

Step-by-step explanation:

We are given that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage of blue candies is equal to 29%.

Let p = population percentage of blue candies

So, Null Hypothesis, $H_0$ : p = 29% {means that the percentage of blue candies is equal to 29%}

Alternate Hypothesis, $H_A$ : p $\neq$ 29% {means that the percentage of blue candies is different from 29%}

The test statistics that will be used here is One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of blue coloured candies = 28%

n = sample of colored candies = 100

So, the test statistics = $\frac{0.28-0.29}{\sqrt{\frac{0.29(1-0.29)}{100} } }$

= -0.22

The value of the z-test statistics is -0.22.

Also, the P-value of the test statistics is given by;

P-value = P(Z < -0.22) = 1 - P(Z $\leq$ 0.22)

= 1 - 0.5871 = 0.4129

Now, at a 0.10 level of significance, the z table gives a critical value of -1.645 and 1.645 for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of z, so we insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the percentage of blue candies is equal to 29%.

4 0

3 years ago

A gardener has 27 pansies and 36 daisies. He plants an equal number of each type of flower in each row. What is the greatest pos

Sergio [31]

Answer:

Step-by-step explanation:

36 can go into 3

27 can go into 3

7 0

3 years ago

Read 2 more answers