Answer:
<h2>8.92 g/cm³</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 4.75 g
volume = 0.5325 cm³
We have
We have the final answer as
<h3>8.92 g/cm³</h3>
Hope this helps you
Answer: 0.72 litres of water is wasted in one day.
Explanation:
First you need to find out how many minutes are in a day. Do this by multiplying the number of minutes in an hour (60) by the number of hours in a day (24). 24 x 60 = 1440. If the faucet is dripping at 5 drops per minute, then multiply 5 by the number of minutes in a day (1440) to see how many drops drip in one day. 5 x 1440 = 7200. Now we need to figure out how many mL fo water that is. if 10 drops is 1 mL, then we need to divide the total number of drops (7200) by 10. 7200 divided by 10 is 720. That means 720 mL of water is dripping per day. Finally, we must convert mL to litres. There are 1000 mL in one litre, so divide 720 by 1000. The final answer is 0.72
The density of the liquid is 0.98 g/mL
<h3>What is density? </h3>
The density of a substance is defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as:
Density = mass / volume
With the above formula, we can obtain the density of the liquid.
<h3>How to determine the density </h3>
- Mass = 30.8 g
- Volume = 31.5 mL
- Density =?
Density = mass / volume
Density of liquid = 30.8 / 31.5
Density of liquid = 0.98 g/mL
Learn more about density:
brainly.com/question/952755
Answer:
The half-life time, the team equired for a quantity to reduce to half of its initial value, is 79.67 seconds.
Explanation:
The half-life time = the time required for a quantity to reduce to half of its initial value. Half of it's value = 50%.
To calculate the half-life time we use the following equation:
[At]=[Ai]*e^(-kt)
with [At] = Concentration at time t
with [Ai] = initial concentration
with k = rate constant
with t = time
We want to know the half-life time = the time needed to have 50% of it's initial value
50 = 100 *e^(-8.7 *10^-3 s^- * t)
50/100 = e^(-8.7 *10^-3 s^-1 * t)
ln (0.5) = 8.7 *10^-3 s^-1 *t
t= ln (0.5) / -8.7 *10^-3 = 79.67 seconds
The half-life time, the team equired for a quantity to reduce to half of its initial value, is 79.67 seconds.
