The student who did the most work is student 2 with 2500 Joules.
<u>Given the following data:</u>
To determine which of the students did the most work:
Mathematically, the work done by an object is given by the formula;

<u>For </u><u>student 1</u><u>:</u>

Work done = 600 Joules
<u>For </u><u>student 2</u><u>:</u>

Work done = 2500 Joules.
Therefore, the student who did the most work is student 2 with 2500 Joules.
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Answer: 0.5
Explanation:
The modulus of elasticity (called <em>"alargamiento unitario"</em> in spanish)
of a spring is given by the following formula:
Where:
is the original length of the spring
is the elongation of the spring, being
the length of the spring after a force is applied to it.
Then:
Answer:
33.6 Ns backward.
Explanation:
Impulse: This can be defined as the product of force and time. The S.I unit of impulse is Ns.
From Newton's second law of motion,
Impulse = change in momentum
I = mΔv................................. Equation 1
Where I = impulse, m = mass of the skater, Δv = change in velocity = final velocity - initial velocity.
Given: m = 28 kg, t = 0.8 s, Δv = -1.2-0 = -1.2 m/s (Note: the initial velocity of the skater = 0 m/s)
Substituting into equation 1
I = 28(-1.2)
I = -33.6 Ns
Thus the impulse = 33.6 Ns backward.
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