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3 years ago

6

You are stopped a red light and you are in the front car at an intersection. Thinking as a defensive driver, describe what your

actions will be when the light turns green.

1 answer:

Airida [17]3 years ago

8 0

Proceed to go when the light turns green with caution watching out for other drivers to prevent and accident

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A point charge q1=+5.00nC is at the fixed position x=0, y=0, z=0. You find that you must do 8.10×10−6J of work to bring a second

Maru [420]

The value of the second charge is 1.2 nC.

<h3>Electric potential</h3>

The work done in moving the charge from infinity to the given position is calculated as follows;

W = Eq₂

E = W/q₂

<h3>Magnitude of second charge</h3>

The magnitude of the second charge is determined by applying Coulomb's law.

$E = \frac{kq_2}{r^2} \\\\\frac{kq_2}{r^2} = \frac{W}{q_2} \\\\kq_2^2 = Wr^2\\\\q_2^2 = \frac{Wr^2}{k} \\\\q_2 = \sqrt{\frac{Wr^2}{k} } \\\\q_2 = \sqrt{\frac{(8.1 \times 10^{-6}) \times (0.04)^2}{9\times 10^9} } \\\\q_2 = 1.2 \times 10^{-9} \ C\\\\q_2 = 1.2 \ nC$

Thus, the value of the second charge is 1.2 nC.

Learn more about electric potential here: brainly.com/question/14306881

7 0

2 years ago

Would sound travel faster in a thick piece of metal (high density) or a large hollow piece of metal (low density)?

KiRa [710]

Answer:

See the explanation below

Explanation:

The speed of sound waves can be calculated using the following equation:

$v_{s}=\sqrt{\frac{E}{ro} } \\where:\\E = Young's modulus [GPa]\\ro = density of the material [kg/m^3]$

Let's do the exercise of comparing two materials one denser than the other, as is steel and aluminum

ro_steel = 7500 [kg/m^3]

ro_aluminum = 2700 [kg/m^3]

E_steel = 200 [GPa]

E_aluminum = 70 [GPa]

Now replacing the values in the equation for each material.

$v_{steel}=\sqrt{\frac{200*10^9}{7500}}\\ v_{steel}=5163[m/s]$

And for the aluminum

$v_{aluminum}=\sqrt{\frac{70*10^9}{2700} }\\ v_{aluminum}=5091.75[m/s]$

In this way we can see that sound propagates faster in denser materials.

6 0

3 years ago

An object of volume 0.0004m^3 and density 6000kg/m^3 is immersed inside a fluid of density 5000kg/m^3. The force exerted by the

FromTheMoon [43]

We have that the density of the fluid is

$\rho_f=178.57 kg/m3$

From the question we are told that

object of volume 0.0004m^3

density 6000kg/m^3

fluid of density 5000kg/m^3.

Force F=0.7N

Generally the equation for the Force is mathematically given as

$F= v*\rho_f*g\\\\0.7= 0.0004*\rho_f*9.8\\\\\rho_f=\frac{0.7}{0.0004*9.8}$

$\rho_f=178.57 kg/m3$

For more information on this visit

brainly.com/question/13338592?referrer=searchResults

8 0

3 years ago

Martha was leaning out of the window on the second floor of her house and speaking to Steve. Suddenly, her glasses slipped from

DiKsa [7]

Answer:

s = 23.72 m

v = 21.56 m/s²

Explanation:

given

time to reach the ground (t) = 2.2 second

we know that

a) s = u t + 0.5 g t²

u = 0 m/s

g = 9.8 m/s²

s = 0 + 0.5 × 9.8 × 2.2²

s = 23.72 m

b) impact velocity

v = √(2gh)

v = √(2× 9.8 × 23.72)

v = √464.912

v = 21.56 m/s²

6 0

4 years ago

Electromagnets are created by (2 points)

KIM [24]

I believe the correct answer is B

5 0

3 years ago