How to find the fourth term of a binomial expansion?
1 answer:
So let's look at how to expand a binomial.. Start with just the variable exponents which will be numbered in ascending and descending order. example (without coefficients) (x+y)^3 = x^3(y^0) + x^2(y^1) + x^1(y^2) + x^0(y^3) If the binomial is (x-y)^3 the +/- signs will toggle like so.. (again leaving out coefficients) (x-y)^3 = x^3(y^0) - x^2(y^1) + x^1(y^2) - x^0(y^3) If there is a coefficient or power inside the binomial like (x^2+2y)^3 these are also raised to the appropriate power. (x^2+2y)^3 = (x^2)^3(y^0)(2^0) + (x^2)^2(y^1)(2^1) + .... now there are also coefficients for each term which follow a combination pattern of Pascal triangle. C(3,0) ; C(3,1) ; C(3,2) ; C(3,3) these get multiplied by each term. So the 4th term of (x^2-2y)^3 will be negative have coefficient of: C(3,3) * (2^3) = 8 variables: x^0(y^3) = y^3 = -8y^3
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