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Tasya [4]
3 years ago
8

What is the solution to the system of equations?

Mathematics
1 answer:
tresset_1 [31]3 years ago
6 0
A system of equation are a set or collection of equations altogether at once
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A car company is designing a car that uses 12% less steel than
Olin [163]

Answer:

180 pound

Step-by-step explanation:

<h3><u>p</u><u>e</u><u>r</u><u>c</u><u>e</u><u>n</u><u>t</u><u>a</u><u>g</u><u>e</u><u>:</u></h3>

<u>t</u><u>h</u><u>e</u><u> </u><u>v</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>1</u><u>2</u><u>%</u>

  • 12% of 1500 pounds
  • 12/100 × 1500
  • 18,000/100
  • 180

much steel will the new car model use is 180 pound

5 0
2 years ago
Kate just bought a tv that measures 42 inches diagonally, and is 18 inches tall. She wants to place the tv into a 40 inch wide c
VLD [36.1K]

9514 1404 393

Answer:

  yes, about 2.05 inches

Step-by-step explanation:

The Pythagorean theorem can be used to find the width of the TV.

  w^2 +h^2 = d^2

  w = √(d^2 -h^2)

  w = √(42^2 -18^2) = √1440 = 12√10

  w ≈ 37.95 . . . inches

This dimension is less than 40 inches by a margin of ...

  40 -37.95 = 2.05 . . . inches

The TV will fit, with 2.05 inches of space remaining.

3 0
3 years ago
Q2) The following travel times were measured for vehicles traversing a 2,000 ft. segment of an arterial: Vehicle Travel Time (s)
adelina 88 [10]

Answer:

TMS = 45.78 m/s

SMS = 45.66 m/s

Step-by-step explanation:

Vehicle Travel Time (s)

1 40.5

2 44.2

3 41.7

4 47.3

5 46.5

6 41.9

7 43.0

8 47.0

9 42.6

10 43.3

Time mean speed and space mean speed are parameters used to express the speed of a group of vehicles in traffic flow.

Time mean speed is given as the average speed of all the cars

The speed for each vehicle is calculated by dividing the (2000 ft) distance by the time taken by each vehicle to complete that segment of the journey.

Let vehicle = V

Travel time = time

Speed = s

V | Time | speed (ft/s)

1 | 40.5 | 49.383

2 | 44.2 | 45.249

3 | 41.7 | 47.962

4 | 47.3 | 42.283

5 | 46.5 | 43.011

6 | 41.9 | 47.733

7 | 43.0 | 46.512

8 | 47.0 | 42.553

9 | 42.6 | 46.948

10| 43.3 | 46.189

TMS = (Σsᵢ)/N

Σsᵢ = (49.383+45.249+47.962+42.283+43.011+47.733+46.512+42.553+46.948+46.189)

Σsᵢ = 457.823

N = number of vehicles = 10

TMS = 457.823 ÷ 10 = 45.7823 = 45.782 m/s

b) Space mean speed is given as

SMS = N ÷ [Σ (1/sᵢ)]

V | Time | speed | (1/sᵢ)

1 | 40.5 | 49.383 | 0.02025

2 | 44.2 | 45.249 | 0.02210

3 | 41.7 | 47.962 | 0.02085

4 | 47.3 | 42.283 | 0.02365

5 | 46.5 | 43.011 | 0.02325

6 | 41.9 | 47.733 | 0.02095

7 | 43.0 | 46.512 | 0.02150

8 | 47.0 | 42.553 | 0.02350

9 | 42.6 | 46.948 | 0.02130

10| 43.3 | 46.189 | 0.02165

Σ (1/sᵢ) = (0.02025+0.02210+0.02085+0.02365+0.02325+0.02095+0.02150+0.02350+0.02130+0.02165)

Σ (1/sᵢ) = 0.219

SMS = 10 ÷ [Σ (1/sᵢ)] = 10 ÷ 0.219

SMS = 45.662 m/s

Hope this Helps!!!

4 0
3 years ago
Why do you need fewer inches than centimeters to measure the length of the key
kirill [66]
Inches and centimeters are different units of measurement, one English, one metric.  Converting from one to the other requires use of a conversion factor.
One such factor can be derived from    1 inch = 2.54 cm.  This means that one inch is 2.54 times longer than one cm.
6 0
3 years ago
Y = 5x + 1<br> 4x + y = 10<br> System of equations
HACTEHA [7]
Substitution or elimination
3 0
3 years ago
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