Ask question

Ask question

All categories

max2010maxim [7]

2 years ago

9

Find the rate of change: Jame scan earn $300 in royalties for 250 books. Rounded to the nearest cent, what is the rate of change

for James' royalties?

1 answer:

iren [92.7K]2 years ago

6 0

Round to two hundred books

You might be interested in

BBC News had 6,632,512 viewers for its evening bulletin. <br><br> What is the place value of the 3?

VashaNatasha [74]

<span> 6,632,512

</span><span>the place value of the 3 is 30,000

hope it helps</span>

6 0

2 years ago

HURRY PLEASE!! I WILL GIVE BRAINLIEST

user100 [1]

Answer:

1/64

Step-by-step explanation:

1/64=(1/8)^2

1/64=(1/4)^3

6 0

2 years ago

Read 2 more answers

A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei

Arte-miy333 [17]

Answer:

<em>Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom</em>

<em>The null hypothesis is accepted . </em>

<em>Assume the population variances are approximately the same</em>

<u><em>Step-by-step explanation:</em></u>

<u>Explanation</u>:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

<em>The first sample size 'n₁'= 20</em>

<em>mean of the first sample 'x₁⁻'= 17.53 pounds</em>

<em>standard deviation of first sample S₁ = 3.2 pounds</em>

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

<em>The second sample size n₂ = 24</em>

<em>mean of the second sample "x₂⁻"= 14.89 pounds</em>

<em>standard deviation of second sample S₂ = 2.7 poun</em>ds

<u><em>Null hypothesis</em></u><u>:-</u><u><em>H₀</em></u><em>: The Population Variance are approximately same</em>

<u><em>Alternatively hypothesis</em></u><em>: H₁:The Population Variance are approximately same</em>

<em>Level of significance ∝ =0.05</em>

<em>Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42</em>

<em>Test statistic :-</em>

<em> </em> $t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

<em> where </em> $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

$S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}$

<em> substitute values and we get S² = 40.988</em>

<em> </em> $t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$ <em></em>

<em> </em> t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

<u><em>Conclusion</em></u>:-

<em>The null hypothesis is accepted </em>

<em>Assume the population variances are approximately the same.</em>

<em> </em>

<em> </em>

<em> </em>

6 0

2 years ago

A digital rain gauge has an outdoor sensor that collects rainfall and transmits data to an indoor display. Assume you produced a

evablogger [386]

Answer:

a. A continuous graph

b. a straight line graph with a gentle positive slope

c. The graph consists of three straight lines attached end to end, with the first segment being an inclined positively sloped graph, the second segment is an horizontal line while the third segment is a gentle positively sloped straight line

Step-by-step explanation:

a. A continuous graph

Given that the rain gauge is a digital rain gauge, the values transmitted to the indoor display are those collected by the outdoor sensor, we have that the output to the transmitter can be any value within a possible and finite range of values, therefore the graph is continuous

b. Whereby it rained at a constant rate of 0.1 inch per hour over 24-hour period, we have;

i) Whereby the graph is the level of water in the rain gauge over a given period of time, the shape of the graph will be a straight line graph with a gentle positive slope of 0.1 the domain will be from 0 to 24 hours, while the range will be from 0 to 2.4 inches

c) i) Given that i) the rain falls at a constant rate of 0.1 inch per hour for 6 hours, and ii) over the next 6 hours it stops raining, after which iii) it rained 0.2 inch for the next 12 hours, we have;

i) In the first part The graph will be a straight line graph with a gentle positive slope of 0.1, up to the point (6, 0.6)

ii) When the rain stops for 6 hours, from the point (6, 0.6) to the point (12, 0.12) the graph will be an horizontal line

iii) From the point (12, 0.12) to the point (24, 0.24), is represented on the graph by a straight line with a gentle positive slope of 0.2.

7 0

2 years ago

Find the value of the expression:<br><br><br><br> 56 ÷ 7 + 7 × 3

miv72 [106K]

First, you have to apply the order of operations.

Division and multiplication come first here and they go from left to right. So,

56/7 = 8
7*3 = 21
Then, the addition.
8 + 21 = 29.

So the value of your expression is 29.

3 0

3 years ago

Read 2 more answers