Find the roots of the equation x3-3x^2+x+5

1 answer:

3 0

X^3-3x^2+x+5=(x+1)(x^2-4x+5)

(x+1)(x^2-4x+5)=0
x+1=0→x+1-1=0-1→x=-1
x^2-4x+5 different to zero

The root of the equation is x=-1

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