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Inga [223]
3 years ago
14

Evaluate 2.5(8.6/2)-1.8

Mathematics
1 answer:
777dan777 [17]3 years ago
3 0

Step-by-step explanation:

Given the expression:

2.5( \frac{8.6}{2} ) - 1.8

Follow BODMAS rule.

always evaluate brackets first, followed by multiply or division then addition or subtraction from LEFT to RIGHT.

2.5( \frac{8.6}{2} ) - 1.8 \\  = 2.5(4.3) - 1.8 \\  = 10.75 - 1.8 \\  = 8.95

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A. 60<br> b. 180<br> c. 100<br> d. 120
Leno4ka [110]

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120 is the correct answer

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6 0
3 years ago
I am wondering Jake finished race at 24.53 18.44 Lacie finished the race at 18.44. What is the difference between Lacie's time a
Dvinal [7]

Answer:

The difference between the times is just 6.09

Step-by-step explanation:

Here, we are interested in finding the difference between the times when two athletes finished their races.

While one finished at 24.53, the other finished at 18.44; So the difference between the two will be calculated by subtracting the time which was less from the time which was more;

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4 0
2 years ago
51
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Answer:

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Step-by-step explanation:

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5 0
2 years ago
Evaluate the expression
larisa86 [58]

Answer:

12-[20-2(6^2\div3\times2^2)]=88

Step-by-step explanation:

So we have the expression:

12-[20-2(6^2\div3\times2^2)]

Recall the order of operations or PEMDAS:

P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.

E: Within the parentheses, if exponents are present, do them before all other operations.

M/D: Multiplication and division next, whichever comes first.

A/S: Addition and subtraction next, whichever comes first.

(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)

Thus, we should do the operations inside the parentheses first. Therefore:

12-[20-2(6^2\div3\times2^2)]

The parentheses is:

(6^2\div3\times2^2)

Square the 6 and the 4:

(36\div3\times4)

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

(36\div3\times4)\\=(12\times4)\\=48

Therefore, the original equation is now:

12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]

Multiply with the brackets:

=12-[20-96]

Subtract with the brackets:

=12-[-76]

Two negatives make a positive. Add:

=12+76=88

Therefore:

12-[20-2(6^2\div3\times2^2)]=88

3 0
3 years ago
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