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konstantin123 [22]
3 years ago
10

-4rover4+5rover3 please help me

Mathematics
1 answer:
Alchen [17]3 years ago
5 0

Solution, \frac{-4r}{4}+\frac{5r}{3}=\frac{2r}{3}

Steps:

\frac{-4r}{4}+\frac{5r}{3}

\frac{-4r}{4},\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b},\\-\frac{4r}{4},\\\mathrm{Divide\:the\:numbers:}\:\frac{4}{4}=1,\\-r,\\-r+\frac{5r}{3}

\mathrm{Convert\:element\:to\:fraction}:\quad \:r=\frac{r3}{3},\\\frac{5r}{3}-\frac{r\cdot \:3}{3}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c},\\\frac{5r-r\cdot \:3}{3}

5r-r\cdot \:3,\\\mathrm{Add\:similar\:elements:}\:5r-3r=2r,\\\frac{2r}{3}

The\:Correct\:Answer\:Is\:\frac{2r}{3}

Hope\:This\:Helps!!!

-Austint1414

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