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nasty-shy [4]
3 years ago
13

Suppose that two sources of sound produce waves of the same exact amplitude and frequency, but are out of phase by one-half of a

wavelength. What will the end result be?
A. You would hear two different sounds of equal volume and pitch.

B. You would hear a sound that's twice as intense, since the waves are complementing each other.

C. You would hear pulsations in the waves at certain intervals, known as beats.

D.You wouldn't hear any sound since the waves are canceling each other out.
Physics
2 answers:
tia_tia [17]3 years ago
8 0

Answer:

option D is right

........

andrezito [222]3 years ago
3 0

Answer:

D) You wouldn't hear any sound since the waves are canceling each other out.

Explanation:

Suppose two sound waves with same amplitude,frequency and \phi phase difference are given by as follows,

y_1=A \ sin\ ( wt+ \phi)

y_2=A\ sin\ wt

Since waves are out of phase by = \frac{\lambda}{2}, phase difference \phi =\pi

hence, resultant displacement

y=y_1+y_2 = A\ sin\ wt + A\ sin\ (wt +\pi  ) = A\ sin\ wt\ - A\ sin\ wt =0

Hence we wouldn't hear any sound since the waves are canceling each other out.

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Answer:

Pure research is conducted without any specific goal in mind. Applied research is conducted in order to solve a specific and practical problem, unlike pure research. Hope this helped.

8 0
3 years ago
At what location in a circuit is the electrical potential energy the greatest
Eduardwww [97]

It's not the potential energy.  It's just the potential.

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4 0
3 years ago
A car experiences a centripetal acceleration of 4.4 m/s ^2 as ur rounds a corner with a speed of 15 m/s. What is the radius of t
damaskus [11]
The calculation of the centripetal acceleration of an object following a circular path is based on the equation,

                  a = v² / r

where a is the acceleration, v is the velocity, and r is the radius.

Substituting the known values from the given above,

             4.4 m/s² = (15 m/s)² / r

The value of r from the equation is 51.14 m.

Answer: 51.14 m
3 0
3 years ago
a 1600 kg car on flat ground is moving 6.25 m/s. its engine creates 1150 N forward force as the car moves 45.8 m. what is it fin
Sveta_85 [38]

Answer:

83,900 J

Explanation:

First, find the acceleration:

F = ma

1150 N = (1600 kg) a

a = 0.719 m/s²

Now find the final velocity.

Given:

Δx = 45.8 m

v₀ = 6.25 m/s

a = 0.719 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (6.25 m/s)² + 2 (0.719 m/s²) (45.8 m)

v = 10.2 m/s

Now find the final KE:

KE = ½ mv²

KE = ½ (1600 kg) (10.2 m/s)²

KE = 83,920 J

Rounded to three significant figures, the final kinetic energy is 83,900 J.

6 0
4 years ago
PLS HELP WITH THIS FOR BRAINLIST IF ITS RIGHT
Zolol [24]

Answer:

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5 0
3 years ago
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