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nasty-shy [4]
3 years ago
13

Suppose that two sources of sound produce waves of the same exact amplitude and frequency, but are out of phase by one-half of a

wavelength. What will the end result be?
A. You would hear two different sounds of equal volume and pitch.

B. You would hear a sound that's twice as intense, since the waves are complementing each other.

C. You would hear pulsations in the waves at certain intervals, known as beats.

D.You wouldn't hear any sound since the waves are canceling each other out.
Physics
2 answers:
tia_tia [17]3 years ago
8 0

Answer:

option D is right

........

andrezito [222]3 years ago
3 0

Answer:

D) You wouldn't hear any sound since the waves are canceling each other out.

Explanation:

Suppose two sound waves with same amplitude,frequency and \phi phase difference are given by as follows,

y_1=A \ sin\ ( wt+ \phi)

y_2=A\ sin\ wt

Since waves are out of phase by = \frac{\lambda}{2}, phase difference \phi =\pi

hence, resultant displacement

y=y_1+y_2 = A\ sin\ wt + A\ sin\ (wt +\pi  ) = A\ sin\ wt\ - A\ sin\ wt =0

Hence we wouldn't hear any sound since the waves are canceling each other out.

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An example will help you. Say that you want to calculate the work made by an engine that rotates a propeller with a torque of 1000 Newton*meter over 50 revolution.

The formula is Work = torque * angle.

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3 years ago
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(10p+15,15-10q)=(25,5)​
Harrizon [31]
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2 years ago
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8 0
3 years ago
A barometer accidentally contains 6.5 inches of water on top of the mercury column (so there is also water vapor instead of a va
Alisiya [41]

Answer:

(a). 14.4 lbf/in^2.

(b). 27.8 in, AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.

Explanation:

So, from the question above we are given the following parameters which are going to help us in solving this particular Question;

=> The "barometer accidentally contains 6.5 inches of water on top of the mercury column (so there is also water vapor instead of a vacuum at the top of the barometer)"

=> "On a day when the temperature is 70oF, the mercury column height is 28.35 inches (corrected for thermal expansion)."

With these knowledge, let us delve right into the solution;

(a). The barometric pressure = water vapor pressure + acceleration due to gravity (ft/s^2) × water density(slug/ft^3) × {ft/12 in}^3 × [ height of mercury column + specific gravity of mercury × height of water column].

The barometric pressure= 0.363 + {(62.146) ÷ (12^3) × 390.6425}. = 14.4 lbf/in^2.

(b). { (13.55 × length of mercury) + 6.5 } × (62.15÷ 12^3) = 14.4 - 0.603.

Length of mercury = 27.8 in.

AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.

7 0
3 years ago
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