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nasty-shy [4]
3 years ago
13

Suppose that two sources of sound produce waves of the same exact amplitude and frequency, but are out of phase by one-half of a

wavelength. What will the end result be?
A. You would hear two different sounds of equal volume and pitch.

B. You would hear a sound that's twice as intense, since the waves are complementing each other.

C. You would hear pulsations in the waves at certain intervals, known as beats.

D.You wouldn't hear any sound since the waves are canceling each other out.
Physics
2 answers:
tia_tia [17]3 years ago
8 0

Answer:

option D is right

........

andrezito [222]3 years ago
3 0

Answer:

D) You wouldn't hear any sound since the waves are canceling each other out.

Explanation:

Suppose two sound waves with same amplitude,frequency and \phi phase difference are given by as follows,

y_1=A \ sin\ ( wt+ \phi)

y_2=A\ sin\ wt

Since waves are out of phase by = \frac{\lambda}{2}, phase difference \phi =\pi

hence, resultant displacement

y=y_1+y_2 = A\ sin\ wt + A\ sin\ (wt +\pi  ) = A\ sin\ wt\ - A\ sin\ wt =0

Hence we wouldn't hear any sound since the waves are canceling each other out.

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Answer:

T_{f}  = 17º C

Explanation:

This is a calorimetry problem, where heat is yielded by liquid water, this heat is used first to melt all ice, let's look for the necessary heat (Q1)  

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Water  M = 860 g = 0.860 kg  

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Now let's see what this liquid water temperature is when this heat is released  

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     T_{f1} = 26.0 - 2,664 10⁴ / (0.860 4186)  

     T_{f1} = 26.0 - 7.40  

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The initial temperature of water that has just melted is T₀₂ = 0ª  

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T_{f} = 17º C

 

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