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3 years ago

@alexrobin13 A 62 kg box is lifted 12 meters off the ground. How much work was done?

Physics

2 answers:

34kurt3 years ago

6 0

7291.2! I'm for sure this is the right answer.

nevsk [136]3 years ago

3 0

Given:
weight=62 kgs
height= 12 m
gravity= 9.8
To find:
work done= mass*gravity*height
solution:
w=62*12*9.8
workdone=7291.2 J

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Set the radius to 2.0 m and the velocity to 1.0 m/s. Keeping the radius the same, record the magnitude of centripetal accelerati

jek_recluse [69]

Answer:

$a=4\ m/s^2$

Explanation:

Given that,

Radius, r = 2 m

Velocity, v = 1 m/s

We need to find the magnitude of the centripetal acceleration. The formula for the centripetal acceleration is given by :

$a=\dfrac{v^2}{r}\\\\a=\dfrac{(2)^2}{1}\\\\=4\ m/s^2$

So, the magnitude of centripetal acceleration is $4\ m/s^2$ .

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3 years ago

A 50 kg pitcher throws a baseball with a mass of 0. 15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is

dsp73

The velocity of the pitcher at the given mass is 0.1 m/s.

The given parameters:

Mass of the pitcher, m₁ = 50 kg
Mass of the baseball, m₂ = 0.15 kg
Velocity of the ball, u₂ = 35 m/s

Let the velocity of the pitcher = u₁

Apply the principle of conservation of linear momentum to determine the velocity of the pitcher as shown below;

m₁u₁ = m₂u₂

$u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{0.15 \times 35}{50} \\\\u_1 = 0.105 \ m/s\\\\u_1 \approx 0.1 \ m/s$

Thus, the velocity of the pitcher at the given mass is 0.1 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/13589460

4 0

2 years ago

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Luden [163]

The correct answer is 3 wiv 2=6

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3 years ago

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Oxana [17]

Answer:

The answer to your question is: V2 = 1 l

Explanation:

Data

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Formula

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V2 = (P1V1) / P2

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3 years ago

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alekssr [168]

Explanation:

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3 0

3 years ago