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KiRa [710]
3 years ago
11

What is the closest star that could go supernova?

Physics
1 answer:
sweet [91]3 years ago
6 0
The nearest star that can go supernova is either Spica or IK Pegasi
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An electric dipole having dipole moment of magnitude p is placed in a uniform electric field having magnitude E. What is the mag
Daniel [21]

Answer:

Explanation:

The formula for the potential energy of a dipole placed in an electric field is given by

U = - pE Cos θ

where, θ is the angle between dipole moment and the electric field vector.

For θ = 0°,

initial potential energy, Ui = - pE

For θ = 180°,

final potential energy, Uf = - pE Cos 180 = pE

Change in potential energy

ΔU = Uf - Ui

ΔU = pE - (-pE)

ΔU = 2pE

5 0
4 years ago
Matter that does not transmit any light.
eduard

Answer:

They all travel at the same speed

Explanation:  the speed of light — in a vacuum, but when they come into contact with matter, they slow down. ... Opaque objects transmit little or no visible light, translucent objects transmit some, and transparent objects transmit almost all, which is why we can see through them.

4 0
3 years ago
During a supernova, the outer layers of a star are blown off and the star's core shrinks down by a factor of 10,000 or more to f
Lana71 [14]

Answer:

a. the core will spin faster.

Explanation:

By law of conservation of angular momentum

(mvR)i= (mvR)f

m= mass of star

v= speed of star

R= radius of star

i= initial

f= final

since, size(R) of the star is reduced by factor of 10,000 and mass remains the same, the velocity must increase by the same factor to keep the angular momentum conserved.

Hence, a. the core will spin faster.

8 0
4 years ago
14. A ball initially at rest rolls without slipping
elena-s [515]

Answer:

v = √(10gh/7)

Explanation:

Initial gravitational energy = final rotational energy + kinetic energy

PE = RE + KE

mgh = ½ Iω² + ½ mv²

For a solid sphere, I = ⅖ mr².

For rolling without slipping, ω = v/r.

mgh = ½ (⅖ mr²) (v/r)² + ½ mv²

mgh = ⅕ mv² + ½ mv²

mgh = 7/10 mv²

10/7 gh = v²

v = √(10gh/7)

7 0
3 years ago
I want to make a Twinkie splat when I throw it off a building. Because Twinkies are notoriously hard to crush, I want it to hit
Monica [59]

Answer:

s=253.6524712 \approx 253.7

Explanation:

From the question we are told that

Initial speedv=8ft/s

Final speed v=128ft/s

Generally the Newtons  equation of motion is mathematically represented by

V_f^2-V_0^2=2as

with

Therefore

a=g=>9.81m/s^2\\a=32.17ft/s^2

Therefore

128^2-8^2=2*(32.17)*s

16320=2*(32.17)*s

s=\frac{16320}{2*(32.17)}

s=253.6524712 \approx 253.7

3 0
3 years ago
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