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ki77a [65]
4 years ago
13

A man standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down the man continues

moving forward at the original speed. This is an example of the effect of
a. gravity.
b. weight.
c. velocity.
d. inertia.
Physics
2 answers:
never [62]4 years ago
8 0
Matter has a property that makes it have a tendency to remain at its original motion. We call this property inertia. This is also the reason why a man standing on the bus continues moving forward despite the bus slowing down. He will have the tendency to go to the same direction prior to the change. Thus, the answer is D: inertia<span>.</span>
Inessa05 [86]4 years ago
5 0
D. Inertia because i got it right in my test

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Internal thermal energy is given as

Q = mCT

so it will depend on the product of mass, specific heat capacity and temperature.

so here we know that both blocks are identical with same initial temperature

So the block with larger mass must have more internal energy

So here the correct answer would be the block with mass 1000g

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3 0
3 years ago
A spacecraft on its way to Mars has small rocket engines mounted on its hull; one on its left surface and one on its back surfac
lozanna [386]

Answer:

v=545.41 \frac{m}{s}

β=-25.93

Explanation:

Give the acceleration in 'x' and 'y' also the time can find the initial velocity using equation of uniform acceleration motion

For axis x

a_{x}=5.10\frac{m}{s^{2}} \\v_{fx}=3780\frac{m}{s} \\v_{fx}=v_{ox}+a_{x}*t\\v_{ox}=v_{fx}-a_{x}*t\\v_{ox}=3780 \frac{m}{s}-5.1\frac{m}{s^{2} }*645s\\v_{ox}=490.5\frac{m}{s}

For axis y

a_{y}=7.30\frac{m}{s^{2}} \\v_{fy}=4470\frac{m}{s} \\v_{fy}=v_{oy}+a_{y}*t\\v_{oy}=v_{fy}-a_{y}*t\\v_{oy}=4470\frac{m}{s}-7.30\frac{m}{s^{2} }*645s\\v_{oy}=-238.5\frac{m}{s}

Maginuted

v=\sqrt{v_{xo}^{2} +v_{yo}^{2} } \\v=\sqrt{490.5x^{2} +(-238.5)^{2} }\\v=545.41 \frac{m}{s}

The  direction is knowing when find the angle so

\beta =tan^{-1}*\frac{v_{yo} }{v_{xo}}\\\beta =tan^{-1}*\frac{-238.5}{490.5}\\\beta =tan^{-1}*-0.48\\\beta =-25.93

4 0
3 years ago
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Usimov [2.4K]

According to Ohm's law for a portion of the circuit we have:

U=RI=>I=U/R=24/3=8 A

The correct answer is  B


3 0
3 years ago
How does the structure of the stigma aid in pollination
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<span>Pollination is the process by which pollen is transferred to the female part of a plant. The stigma is the central part of the flower, that is supported by a style and is part of the female reproductive organ within plants. Its structure is optimised to promote pollination by having hairs, sticky surfaces and three-dimensional sculptures that capture and trap pollen.</span>
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3 years ago
A 250 kg flatcar 25 m long is moving with a speed of 3.0 m/s along horizontal frictionless rails. A 61 kg worker starts walking
Anna11 [10]

Answer:

x=31.09m

Explanation:

p1=p2

The momentum of flatcar and the momentum of the worker so

The velocity of the worker is:

m_{f}*v_{f}=m_{w}*v_{w}\\\\v_{f}=\frac{m_{f}*v_{f}}{m_{w}}\\v_{f}=\frac{61kg*3.0\frac{m}{s}}{250kg}\\v_{f}=0.732\frac{m}{s}

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Vt=v_{w}+v_{f}\\Vt=0.732\frac{m}{s}+3.0\frac{m}{s}\\Vt=3.732\frac{m}{s}

The time the worker take walking is

t=\frac{x}{v_{w}}\\t=\frac{25m}{3\frac{m}{s}}=8.33s

Now the total time and the total velocity determinate the motion of tha flatcar how far has moved

x=t*Vt\\x=8.33s*3.732\frac{m}{s} \\x=31.09m

5 0
3 years ago
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