The RDS-220 <span>hydrogen bomb, soviet </span>
<span>R = rate of flow = 0.370 L/s
H = height = 2.9 m
T= time = 3.9 s
V = velocity of water when it hits the bucket = sqrt(2gh) = sqrt(2 x 9.8 x 2.9) =7.539 m/s2
G value = 9.8 m/s2
Wb = weight of bucket = 0.690 kg x 9.8 m/s2 = 6.762 N
Wa = weight of accumulated water after 3.9 s
Fi = force of impact of water on the bucket
S = reading on the scale = Wa + Wb + Fi
mass of water accumulated after 3.9 s = R x T = 0.370 x 3.9 = 1.443 L = 1.443 kg
Therefore, Wa = 1.443 x 9.8 = 14.1414 N
Fi = rate of change of momentum at the impact point = R x V (because R = dm/dt)
= 0.37 x 7.539 = 2.78943 N
S = 14.1414 + 6.762 + 2.78943 = 23.692 N</span>
The moment of inertia of a uniform solid sphere is equal to 0.448
.
<u>Given the following data:</u>
Mass of sphere = 7 kg.
Radius of sphere = 0.4 meter.
<h3>How to calculate moment of inertia.</h3>
Mathematically, the moment of inertia of a solid sphere is given by this formula:

<u>Where:</u>
- I is the moment of inertia.
Substituting the given parameters into the formula, we have;

I = 0.448
.
Read more on inertia here: brainly.com/question/3406242
Answer:
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Explanation:
Answer:
because
Explanation:
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