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Alika [10]
3 years ago
14

The diameter of a bowling ball is 12.57 centimeters. What is this value rounded to the nearest tenth of a centimeter?

Mathematics
2 answers:
choli [55]3 years ago
6 0
For this case we have the following numerical value:
 12.57 centimeters
 We note that the number is rounded to the nearest hundredth.
 If we want to round the number to the nearest decimal we must rewrite the number.
 Rewriting we have:
 12.6 centimeters
 Answer:
 
this value rounded to the nearest tenth of a centimeter is:
 
12.6 centimeters
saw5 [17]3 years ago
5 0
12.6 cm is the correct answer.
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Marizza181 [45]
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multiply both sides by 3/2:-

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8 0
3 years ago
Jack took a test and got 13 out of 17 points. He took a make-up test and got 12 out of 15 points.
blagie [28]

Answer:

4.6

Step-by-step explanation:

The answer is 4.6%, hope it helps! sorry if wrong!

3 0
3 years ago
A coordinator will select 6 songs from a list of 9 songs to compose an event's musical entertainment lineup. How many different
g100num [7]

Answer:

84 different lineups are possible

Step-by-step explanation:

The order in which the songs are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

6 musics from a set of 9. So

C_{9,6} = \frac{9!}{6!(9-6)!} = 84

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4 0
3 years ago
What is the volume of a hemisphere with a radius of 3 cm, rounded to the nearest tenth of a cubic centimeter?
Kaylis [27]

Formula: V = (2/3) π r 3.

Radius is 3cm.

So, now we can plug it in to solve for the volume.

V = (2/3) π 3^3

First, let's multiply 3^3.

3^3 = 27

Then, 27 x π = 84.82

After, multiply by 2/3.

84.82 x 2/3 = 56.55

Lastly, round 56.55 to the nearest tenth of a cubic centimeter.

56.55 = 56.6

Therefore the volume of a hemisphere with a radius of 3cm is 56.6cm^3.

8 0
2 years ago
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Ludmilka [50]

Answer:

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Step-by-step explanation:

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2 years ago
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