What is the term for an area of a country located away from capital?

You can comfortably hold your fingers close beside a candle flame, but not very close above the flame. why? challenge (optional)

Inessa05 [86]

The candle flame releases hot gases, which directly go in upwards directions. Due to which the air near the flame of the candle is very hot and dense. The particles along with vapour move up. And since the sideways, the air is not very dense and hot, we are able to hold the candle. In anti-gravity region, there will be no density differences and also, the convection process wont occur. So, the candle quickly snuffs off.

6 0

3 years ago

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How does the direction of the electric current, moving across a battery powered device, differ from the direction of travel in t

svetoff [14.1K]

They both have different wave traction's

8 0

3 years ago

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There is a 90 kg woman attached at the end of a bungee cord (k = 35 N/m) that is experiencing simple harmonic motion. How long d

Cloud [144]

Answer:

The value is $T =10.1 \ s$

Explanation:

From the question we are told that

The mass of the woman is $m = 90 \ kg$

The spring constant of the bungee cord is $k = 35 \ N/ m$

Generally the period of the oscillation (i,e time taken to complete on cycle ) is mathematically represented as

$T = 2 \pi * \sqrt{ \frac{m}{k} }$

=> $T = 2 * 3.142 * \sqrt{ \frac{90 }{ 35} }$

=> $T =10.1 \ s$

3 0

3 years ago

3. Sailors use a capstan (shown below) to raise and lower the anchor. It takes two sailors located 1 meter from the center to tu

mr_godi [17]

Answer:

B. 2 meters.

Explanation:

To rotate the capstan a certain amount of torque is required, and if each sailor applies a force $F$ at a distance $D$ from the center, then for two sailors the total torque will be

$\tau = 2FD\\$ ;

therefore, for one sailor to apply the same torque it must be that the torque $\tau_2$ he applies must be equal to the torque that the two sailors applied:

$FD_2 =2FD$

which gives

$D_2 = 2D$ .

and since $D = 1\:meter$ ,

$\boxed{D_2 = 2\: meters}$

which is choice B.

4 0

3 years ago

In unit-vector notation, what is the torque about the origin on a particle located at coordinates (0 m, −3.0 m, 2.0 m) due to fo

irinina [24]

Answer:

The torque about the origin is $2.0Nm\hat{i}-8.0Nm\hat{j}-12.0Nm\hat{k}$

Explanation:

Torque $\overrightarrow{\tau}$ is the cross product between force $\overrightarrow{F}$ and vector position $\overrightarrow{r}$ respect a fixed point (in our case the origin):

$\overrightarrow{\tau}=\overrightarrow{r}\times\overrightarrow{F}$

There are multiple ways to calculate a cross product but we're going to use most common method, finding the determinant of the matrix:

$\overrightarrow{r}\times\overrightarrow{F} =-\left[\begin{array}{ccc} \hat{i} & \hat{j} & \hat{k}\\ F1_{x} & F1_{y} & F1_{z}\\ r_{x} & r_{y} & r_{z}\end{array}\right]$

$\overrightarrow{r}\times\overrightarrow{F} =-((F1_{y}r_{z}-F1_{z}r_{y})\hat{i}-(F1_{x}r_{z}-F1_{z}r_{x})\hat{j}+(F1_{x}r_{y}-F1_{y}r_{x})\hat{k})$

$\overrightarrow{r}\times\overrightarrow{F} =-((0(2.0m)-0(-3.0m))\hat{i}-((4.0N)(2.0m)-(0)(0))\hat{j}+((4.0N)(-3.0m)-0(0))\hat{k})$

$\overrightarrow{r}\times\overrightarrow{F}=-2.0Nm\hat{i}+8.0Nm\hat{j}+12.0Nm\hat{k}=\overrightarrow{\tau}$

4 0

3 years ago