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Kobotan [32]
3 years ago
12

what’s 55mph to km/min? can someone explain to to me with the work so i can understand how to solve this

Physics
2 answers:
natali 33 [55]3 years ago
6 0

Answer:

55 miles / hour = 1.475232 kilometers / minute

AnnZ [28]3 years ago
3 0
Hope this helps your answer pretty much :3

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What is the actual depth of rainfall shown in this rain gauge?
ehidna [41]

Answer:

The answer is D.

Explanation:

As shown in the picture, the measuring tube is collecting 10 cm of rain.

6 0
3 years ago
Read 2 more answers
9) What would be the weight of a 59.1-kg astronaut on a planet with the same density as Earth and having twice Earth's radius?
Hunter-Best [27]
The weight of the astronaut is given by
W=mg
where m=59.1 kg is his mass and g=9.81~m/s^2 is the gravitational acceleration on Earth. 

To solve the problem, we must find the value of g on the new planet. g is given by
g= \frac{GM}{r^2}
where G is the gravitational constant, M the mass of the planet and r its radius. 
The mass of the planet can be written as
M=dV
where d is the density and V the volume.
We can assume that the planet is a sphere, therefore the volume is proportional to r^3:
V= \frac{4}{3}\pi r^3
and we can write the mass as
M= \frac{4}{3} \pi d r^3
and then, g becomes
g= \frac{GM}{r^2}= \frac{4}{3} \frac{G \pi d r^3}{r^2}= \frac{4}{3} G \pi d r
So, in the end g is proportional to the radius of the planet, r (because the density of the new planet d is the same as the Earth's one. If the radius of the new planet is twice the Earth's radius, g will be twice the value of g on Earth:
g_{new}=2g=2\cdot9.81~m/s^2=19.62~m/s^2
And since the mass of the astronaut is always the same, the weight on the new planet will be twice the weight on Earth:
W_{new}=mg_{new}=2mg=1159~N
5 0
3 years ago
White light, with frequencies ranging from 4.00 x 10^14 Hz to 7.90 x 10^14 Hz, is incident on a barium surface. Given that the w
REY [17]

Answer:

0.7515875 eV

4\times 10^{14}\leq f

Explanation:

f = Maximum frequency = 7.9\times 10^{14}\ Hz

h = Planck's constant = 6.626\times 10^{-34}\ m^2kg/s

W = Work function = 2.52 eV

Converting to Joules

W=2.52\times 1.6\times 10^{-19}\\\Rightarrow W=4.032\times 10^{-19}\ J

Maximum photon energy is given by

E=hf\\\Rightarrow E=6.626\times 10^{-34}\times 7.9\times 10^{14}\\\Rightarrow E=5.23454\times 10^{-19}\ J

Maximum Kinetic energy is given by

K=E-W\\\Rightarrow K=5.23454\times 10^{-19}-4.032\times 10^{-19}\\\Rightarrow K=1.20254\times 10^{-19}\ J

Converting to eV

1.20254\times 10^{-19}\times \frac{1}{1.6\times 10^{-19}}=0.7515875\ eV

The maximum kinetic energy of electrons ejected from this surface is 0.7515875 eV

W=hf\\\Rightarrow f=\frac{W}{h}\\\Rightarrow f=\frac{4.032\times 10^{-19}}{6.626\times 10^{-34}}\\\Rightarrow f=6.08512\times 10^{14}\ Hz

The range of frequencies for which no electrons are ejected is

4\times 10^{14}\leq f

5 0
2 years ago
A chemist identifies compounds by identifying bright lines in their spectra. She does so by heating the compounds until they glo
padilas [110]

Answer:

 a)    λ = 189.43 10⁻⁹ m  b)    λ = 269.19 10⁻⁹ m

Explanation:

The diffraction network is described by the expression

      d sin θ= m λ

Where m corresponds to the diffraction order

Let's use trigonometry to find the breast

        tan θ = y / L

The diffraction spectrum is measured at very small angles, therefore

      tan θ = sin θ / cos θ = sin θ

We replace

      d y / L = m λ

Let's place in the first order m = 1

Let's look for the separation of the lines (d)

     d = λ  L / y

     d = 501 10⁻⁹ 9.95 10⁻² / 15 10⁻²

     d = 332.33 10⁻⁹ m

Now we can look for the wavelength of the other line

     λ  = d y / L

    λ  = 332.33 10⁻⁹ 8.55 10⁻²/15 10⁻²

    λ = 189.43 10⁻⁹ m

Part B

The compound wavelength B

      λ  = 332.33 10⁻⁹ 12.15 10⁻² / 15 10⁻²

      λ = 269.19 10⁻⁹ m

4 0
3 years ago
What is formed when the rock making up a tectonic plate breaks and moves Select one of the options below as your answer:
dem82 [27]

A. a fault hopes this helps you guys

6 0
3 years ago
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