1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tresset_1 [31]
3 years ago
11

Hwueuehhdhdhehdhsijsjsjdjhh​

Physics
2 answers:
jeka943 years ago
6 0
The arrow in the chemical equation is it “turns into”


(I hope it helps)
aivan3 [116]3 years ago
3 0
The arrow in chemical equation means 'turns into' i think
You might be interested in
Twenty grams of a solid at 70°C is place in 100 grams of a fluid at 20°C. Thermal equilibrium is reached at 30°C.
zaharov [31]

Answer:

c. is more than that of the fluid.

Explanation:

This problem is based on the conservation of energy and the concept of thermal equilibrium

heat= m s \Delta T


m= mass

s= specific heat

\DeltaT=change in temperature

let s1= specific heat of solid and s2= specific heat of liquid

then

Heat lost by solid= 20(s_1)(70-30)=800s_1


Heat gained by fluid=100(s_2)(30-20)=1000s_2


Now heat gained = heat lost

therefore,

1000 S_2=800 S_1

S_1=1.25 S_2

so the specific heat of solid is more than that of the fluid.

8 0
3 years ago
Which option is part of designing a set of experimental procedures
-BARSIC- [3]

determining how data will he gathered

Explanation: Apex

7 0
3 years ago
A 1090 kg car has four 12.7 kg wheels. When the car is moving, what fraction of the total kinetic energy of the car is due to ro
max2010maxim [7]

Answer:

\frac{KE_{Rotational}}{KE_{Total}} = 0.018

Explanation:

To develop this exercise we proceed to use the kinetic energy equations,

In the end we replace

KE_{Total}=KE_{Translational}+KE_{Rotational}

KE_{Total}=\frac{1}{2}m_{car}+4*\frac{1}{2}*I*(\frac{v}{r})^2

Here

I=\frac{1}{2}m_{wheels}*r^2 meaning the 4 wheels,

So replacing

KE_{Rotational}=4\frac{1}{2}*(\frac{1}{2}m_{wheels}*r^2)*(\frac{v}{r})^2=m*v^2

So,

\frac{KE_{Rotational}}{KE_{Total}} = \frac{m_{wheels}*v^2}{\frac{1}{2}m_{car}*v^2+m_{wheels}*v^2}

\frac{KE_{Rotational}}{KE_{Total}} = \frac{m_{wheels}}{\frac{1}{2}m_{car}+m_{wheels}}

\frac{KE_{Rotational}}{KE_{Total}} =  \frac{10}{545+10}

\frac{KE_{Rotational}}{KE_{Total}} = 0.018

3 0
3 years ago
A construction worker is pushing a 50.0-kg box with a force of 150.0 N to the right. If the box is moving at a constant velocity
9966 [12]

Yes omg yes I literally have the same question and need to find the answer
7 0
2 years ago
What is one major difference between the attributes of Mercury and Jupiter? A. Mercury is the planet that is closest to the Sun,
sergeinik [125]

The major difference is: Mercury has no orbiting satellites, while Jupiter has many satellites that surround it, so the correct answer is C

3 0
3 years ago
Read 2 more answers
Other questions:
  • Photoelectric effect:
    9·1 answer
  • ou purchase a rectangular piece of metal that has dimen- sions 5.0 * 15.0 * 30.0 mm and mass 0.0158 kg. The seller tells you tha
    11·1 answer
  • A 1530 kg car moving south at 12.1 m/s collides with a 2560 kg car moving north. The cars stick together and move as a unit afte
    5·1 answer
  • A toy car is moving across a table with a velocity of 7.0 m/s and drives off the end. The table is 1.8 m tall. How long will the
    7·1 answer
  • A box of mass 115 kg sits on an inclined surface with an angle of 59º. What
    7·1 answer
  • Why is the specific heat of salt solution lower than that of water?
    10·1 answer
  • A capacitor is constructed of two large, identical, parallel metal plates separated by a small distance d. A battery fully charg
    8·1 answer
  • What is the acceleration of softball if it has a mass of 0.5 kg and hits the catcher's
    6·1 answer
  • A ball rolls up a ramp with a velocity of 8.0 m/s. How high up the ramp does it travel?
    8·1 answer
  • 5. a new type of hoverboard has been designed to levitate over a copper surface. the
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!