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Answer:
A
Explanation:
The formula used is
PV = P1 * V1
P = x
P1 = 4x
V1 = 1
V2 = ?
x * 1 = 4x * V2 Divide both sides by x
x/x = 4x /x * V2
1 = 4*V2 Divide by 4
1/4 = 4*V2/4
1/4 = V2
The answer is A
Answer:
<em>The answer to your question is </em><em>c. H2O</em>
Explanation:
<em>a. CaCO3 ----> Calcium Carbonate is obviously not a binary compound because it contains more than two elements. </em>
<em>b. CuSO4 ----> CuSO4 stands for copper(II) sulfate. Sulfate is the polyatomic ion SO4 -2.</em>
<em>c. H2O ----> Binary molecular compounds are composed of only two elements. Examples are H2O, NO, SF6 etc. </em>
<em>d. Pb(NO3)2 ----> Lead(II) nitrate is an inorganic compound with the chemical formula Pb(NO3)2.</em>
<em>I hope this helps and have a great day!</em>
Explanation:
The reaction is as follows.
Standard values of bond energies are as follows.
C-C = 347 kJ/mol
C-H = 414 kJ/mol
C-O = 360 kJ/mol
O-H = 464 kJ/mol
O=O = 498 kJ/mol
C=O = 799 kJ/mol
Hence, calculate the change in enthalpy of the reaction as follows.
= [5(C-H) + 1(C-C) + 1(C-O) + 1(O-H) + 3(O=O)] - [4(C=O) + 6(O-H)]
= ![[5 \times 414 + 1 \times 347 + 1 \times 360 + 1 \times 464 + 3 \times 498] kJ - [4 \times 799 + 6 \times 464]kJ](https://tex.z-dn.net/?f=%5B5%20%5Ctimes%20414%20%2B%201%20%5Ctimes%20347%20%2B%201%20%5Ctimes%20360%20%2B%201%20%5Ctimes%20464%20%2B%203%20%5Ctimes%20498%5D%20kJ%20-%20%5B4%20%5Ctimes%20799%20%2B%206%20%5Ctimes%20464%5DkJ)
= (4735 - 5980) kJ
= -1245 kJ
Thus, we can conclude that the enthalpy of given reaction is -1245 kJ.
